Class Solution
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public final class Solution3342 - Find Minimum Time to Reach Last Room II.
Medium
There is a dungeon with
n x mrooms arranged as a grid.You are given a 2D array
moveTimeof sizen x m, wheremoveTime[i][j]represents the minimum time in seconds when you can start moving to that room. You start from the room(0, 0)at timet = 0and can move to an adjacent room. Moving between adjacent rooms takes one second for one move and two seconds for the next, alternating between the two.Return the minimum time to reach the room
(n - 1, m - 1).Two rooms are adjacent if they share a common wall, either horizontally or vertically.
Example 1:
Input: moveTime = \[\[0,4],4,4]
Output: 7
Explanation:
The minimum time required is 7 seconds.
At time
t == 4, move from room(0, 0)to room(1, 0)in one second.At time
t == 5, move from room(1, 0)to room(1, 1)in two seconds.
Example 2:
Input: moveTime = \[\[0,0,0,0],0,0,0,0]
Output: 6
Explanation:
The minimum time required is 6 seconds.
At time
t == 0, move from room(0, 0)to room(1, 0)in one second.At time
t == 1, move from room(1, 0)to room(1, 1)in two seconds.At time
t == 3, move from room(1, 1)to room(1, 2)in one second.At time
t == 4, move from room(1, 2)to room(1, 3)in two seconds.
Example 3:
Input: moveTime = \[\[0,1],1,2]
Output: 4
Constraints:
2 <= n == moveTime.length <= 7502 <= m == moveTime[i].length <= 750<code>0 <= moveTimej<= 10<sup>9</sup></code>
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final IntegerminTimeToReach(Array<IntArray> moveTime)-
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Method Detail
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minTimeToReach
final Integer minTimeToReach(Array<IntArray> moveTime)
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