Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    154 - Find Minimum in Rotated Sorted Array II.

    Hard

    Suppose an array of length n sorted in ascending order is rotated between 1 and n times. For example, the array nums = [0,1,4,4,5,6,7] might become:

    • [4,5,6,7,0,1,4] if it was rotated 4 times.

    • [0,1,4,4,5,6,7] if it was rotated 7 times.

    Notice that rotating an array [a[0], a[1], a[2], ..., a[n-1]] 1 time results in the array [a[n-1], a[0], a[1], a[2], ..., a[n-2]].

    Given the sorted rotated array nums that may contain duplicates , return the minimum element of this array.

    You must decrease the overall operation steps as much as possible.

    Example 1:

    Input: nums = 1,3,5

    Output: 1

    Example 2:

    Input: nums = 2,2,2,0,1

    Output: 0

    Constraints:

    • n == nums.length

    • 1 <= n <= 5000

    • -5000 <= nums[i] <= 5000

    • nums is sorted and rotated between 1 and n times.

    Follow up: This problem is similar to Find Minimum in Rotated Sorted Array, but nums may contain duplicates. Would this affect the runtime complexity? How and why?

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer findMin(IntArray nums)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait