Package g0901_1000.s0922_sort_array_by_parity_ii

Class Solution

  • All Implemented Interfaces:
    
public final class Solution

    922 - Sort Array By Parity II.

    Easy

    Given an array of integers nums, half of the integers in nums are odd , and the other half are even.

    Sort the array so that whenever nums[i] is odd, i is odd , and whenever nums[i] is even, i is even.

    Return any answer array that satisfies this condition.

    Example 1:

    Input: nums = 4,2,5,7

    Output: 4,5,2,7

    Explanation: 4,7,2,5, 2,5,4,7, 2,7,4,5 would also have been accepted.

    Example 2:

    Input: nums = 2,3

    Output: 2,3

    Constraints:

    • <code>2 <= nums.length <= 2 * 10<sup>4</sup></code>

    • nums.length is even.

    • Half of the integers in nums are even.

    • 0 &lt;= nums[i] &lt;= 1000

    Follow Up: Could you solve it in-place?

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description

    • Field Summary

      Fields 
      Modifier and Type Field Description

    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()

    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description

    • Method Summary

      Modifier and Type Method Description
      final IntArray sortArrayByParityII(IntArray nums)

      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait