Class Solution
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- All Implemented Interfaces:
public final class Solution1606 - Find Servers That Handled Most Number of Requests.
Hard
You have
kservers numbered from0tok-1that are being used to handle multiple requests simultaneously. Each server has infinite computational capacity but cannot handle more than one request at a time. The requests are assigned to servers according to a specific algorithm:The <code>i<sup>th</sup></code> (0-indexed) request arrives.
If all servers are busy, the request is dropped (not handled at all).
If the <code>(i % k)<sup>th</sup></code> server is available, assign the request to that server.
Otherwise, assign the request to the next available server (wrapping around the list of servers and starting from 0 if necessary). For example, if the <code>i<sup>th</sup></code> server is busy, try to assign the request to the <code>(i+1)<sup>th</sup></code> server, then the <code>(i+2)<sup>th</sup></code> server, and so on.
You are given a strictly increasing array
arrivalof positive integers, wherearrival[i]represents the arrival time of the <code>i<sup>th</sup></code> request, and another arrayload, whereload[i]represents the load of the <code>i<sup>th</sup></code> request (the time it takes to complete). Your goal is to find the busiest server(s). A server is considered busiest if it handled the most number of requests successfully among all the servers.Return a list containing the IDs (0-indexed) of the busiest server(s). You may return the IDs in any order.
Example 1:
Input: k = 3, arrival = 1,2,3,4,5, load = 5,2,3,3,3
Output: 1
Explanation:
All of the servers start out available.
The first 3 requests are handled by the first 3 servers in order.
Request 3 comes in. Server 0 is busy, so it's assigned to the next available server, which is 1.
Request 4 comes in. It cannot be handled since all servers are busy, so it is dropped.
Servers 0 and 2 handled one request each, while server 1 handled two requests. Hence server 1 is the busiest server.
Example 2:
Input: k = 3, arrival = 1,2,3,4, load = 1,2,1,2
Output: 0
Explanation:
The first 3 requests are handled by first 3 servers.
Request 3 comes in. It is handled by server 0 since the server is available.
Server 0 handled two requests, while servers 1 and 2 handled one request each. Hence server 0 is the busiest server.
Example 3:
Input: k = 3, arrival = 1,2,3, load = 10,12,11
Output: 0,1,2
Explanation: Each server handles a single request, so they are all considered the busiest.
Constraints:
<code>1 <= k <= 10<sup>5</sup></code>
<code>1 <= arrival.length, load.length <= 10<sup>5</sup></code>
arrival.length == load.length<code>1 <= arrivali, loadi<= 10<sup>9</sup></code>
arrivalis strictly increasing.
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Constructor Summary
Constructors Constructor Description Solution()
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