2070 - Most Beautiful Item for Each Query.

Medium

You are given a 2D integer array items where <code>itemsi = price_i, beauty_i</code> denotes the price and beauty of an item respectively.

You are also given a 0-indexed integer array queries. For each queries[j], you want to determine the maximum beauty of an item whose price is less than or equal to queries[j]. If no such item exists, then the answer to this query is 0.

Return an array answer of the same length as queries where answer[j] is the answer to the <code>j^th</code> query.

Example 1:

Input: items = [1,2,3,2,2,4,5,6,3,5], queries = 1,2,3,4,5,6

Output: 2,4,5,5,6,6

Explanation:

• For queries0=1, 1,2 is the only item which has price <= 1. Hence, the answer for this query is 2.

• For queries1=2, the items which can be considered are 1,2 and 2,4.

The maximum beauty among them is 4.

• For queries2=3 and queries3=4, the items which can be considered are 1,2, 3,2, 2,4, and 3,5.

The maximum beauty among them is 5.

• For queries4=5 and queries5=6, all items can be considered.

Hence, the answer for them is the maximum beauty of all items, i.e., 6.

Example 2:

Input: items = [1,2,1,2,1,3,1,4], queries = 1

Output: 4

Explanation:

The price of every item is equal to 1, so we choose the item with the maximum beauty 4.

Note that multiple items can have the same price and/or beauty.

Example 3:

Input: items = [10,1000], queries = 5

Output: 0

Explanation:

No item has a price less than or equal to 5, so no item can be chosen.

Hence, the answer to the query is 0.

Constraints:

• <code>1 <= items.length, queries.length <= 10⁵</code>

• items[i].length == 2

• <code>1 <= price_i, beauty_i, queriesj<= 10⁹</code>