2164 - Sort Even and Odd Indices Independently.

Easy

You are given a 0-indexed integer array nums. Rearrange the values of nums according to the following rules:

• Sort the values at odd indices of nums in non-increasing order.

• Sort the values at even indices of nums in non-decreasing order.

Return the array formed after rearranging the values of nums.

Example 1:

Input: nums = 4,1,2,3

Output: 2,3,4,1

Explanation:

First, we sort the values present at odd indices (1 and 3) in non-increasing order.

So, nums changes from 4, **1** ,2, **3** to 4, **3** ,2, **1** .

Next, we sort the values present at even indices (0 and 2) in non-decreasing order. So, nums changes from **4** ,1, **2** ,3 to **2** ,3, **4** ,1.

Thus, the array formed after rearranging the values is 2,3,4,1.

Example 2:

Input: nums = 2,1

Output: 2,1

Explanation: Since there is exactly one odd index and one even index, no rearrangement of values takes place.

The resultant array formed is 2,1, which is the same as the initial array.

Constraints:

• 1 <= nums.length <= 100

• 1 <= nums[i] <= 100