2283 - Check if Number Has Equal Digit Count and Digit Value.

Easy

You are given a 0-indexed string num of length n consisting of digits.

Return true if for every index i in the range 0 <= i < n, the digit i occurs num[i] times in num, otherwise return false.

Example 1:

Input: num = "1210"

Output: true

Explanation:

num0 = '1'. The digit 0 occurs once in num.

num1 = '2'. The digit 1 occurs twice in num.

num2 = '1'. The digit 2 occurs once in num.

num3 = '0'. The digit 3 occurs zero times in num.

The condition holds true for every index in "1210", so return true.

Example 2:

Input: num = "030"

Output: false

Explanation:

num0 = '0'. The digit 0 should occur zero times, but actually occurs twice in num.

num1 = '3'. The digit 1 should occur three times, but actually occurs zero times in num.

num2 = '0'. The digit 2 occurs zero times in num.

The indices 0 and 1 both violate the condition, so return false.

Constraints:

• n == num.length

• 1 <= n <= 10

• num consists of digits.