2660 - Determine the Winner of a Bowling Game.

Easy

You are given two 0-indexed integer arrays player1 and player2, that represent the number of pins that player 1 and player 2 hit in a bowling game, respectively.

The bowling game consists of n turns, and the number of pins in each turn is exactly 10.

Assume a player hit <code>x_i</code> pins in the <code>i^th</code> turn. The value of the <code>i^th</code> turn for the player is:

• <code>2x_i</code> if the player hit 10 pins in any of the previous two turns.

• Otherwise, It is <code>x_i</code>.

The score of the player is the sum of the values of their n turns.

Return

• 1 if the score of player 1 is more than the score of player 2,

• 2 if the score of player 2 is more than the score of player 1, and

• 0 in case of a draw.

Example 1:

Input: player1 = 4,10,7,9, player2 = 6,5,2,3

Output: 1

Explanation: The score of player1 is 4 + 10 + 27 + 29 = 46.

The score of player2 is 6 + 5 + 2 + 3 = 16.

Score of player1 is more than the score of player2, so, player1 is the winner, and the answer is 1.

Example 2:

Input: player1 = 3,5,7,6, player2 = 8,10,10,2

Output: 2

Explanation: The score of player1 is 3 + 5 + 7 + 6 = 21.

The score of player2 is 8 + 10 + 210 + 22 = 42.

Score of player2 is more than the score of player1, so, player2 is the winner, and the answer is 2.

Example 3:

Input: player1 = 2,3, player2 = 4,1

Output: 0

Explanation: The score of player1 is 2 + 3 = 5

The score of player2 is 4 + 1 = 5

The score of player1 equals to the score of player2, so, there is a draw, and the answer is 0.

Constraints:

• n == player1.length == player2.length

• 1 <= n <= 1000

• 0 <= player1[i], player2[i] <= 10