Class Solution
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public final class Solution3341 - Find Minimum Time to Reach Last Room I.
Medium
There is a dungeon with
n x mrooms arranged as a grid.You are given a 2D array
moveTimeof sizen x m, wheremoveTime[i][j]represents the minimum time in seconds when you can start moving to that room. You start from the room(0, 0)at timet = 0and can move to an adjacent room. Moving between adjacent rooms takes exactly one second.Return the minimum time to reach the room
(n - 1, m - 1).Two rooms are adjacent if they share a common wall, either horizontally or vertically.
Example 1:
Input: moveTime = [0,4,4,4]
Output: 6
Explanation:
The minimum time required is 6 seconds.
At time
t == 4, move from room(0, 0)to room(1, 0)in one second.At time
t == 5, move from room(1, 0)to room(1, 1)in one second.
Example 2:
Input: moveTime = [0,0,0,0,0,0]
Output: 3
Explanation:
The minimum time required is 3 seconds.
At time
t == 0, move from room(0, 0)to room(1, 0)in one second.At time
t == 1, move from room(1, 0)to room(1, 1)in one second.At time
t == 2, move from room(1, 1)to room(1, 2)in one second.
Example 3:
Input: moveTime = [0,1,1,2]
Output: 3
Constraints:
2 <= n == moveTime.length <= 502 <= m == moveTime[i].length <= 50<code>0 <= moveTimej<= 10<sup>9</sup></code>
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final IntegerminTimeToReach(Array<IntArray> moveTime)-
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Method Detail
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minTimeToReach
final Integer minTimeToReach(Array<IntArray> moveTime)
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