Mailman 3 October 2019 - Matplotlib-users

When was axes kwarg rmoved?
by Vicki Brown Nov. 1, 2019

Nov. 1, 2019

I'm hoping someone can tell me (point me to the ChanegLog for) when he axes kwarg was removed from matplotlib.pyplot.clabel, matplotlib.pyplot.contou, and matplotlib.pyplot.contourf. My search has turned up nothing. I have code in an exercise for a class that called: plt.contourf(xx, yy, Z, cmap=ccolor, alpha=.2, axes=ax) cs2 = plt.contour(xx, yy, Z, cmap=ccolor, alpha=.6, axes=ax) plt.clabel(cs2, fmt = '%2.1f', colors = 'k', fontsize=14, axes=ax) when run, this raised errors. I've changed it to ax.contourf(xx, yy, Z, cmap=ccolor, alpha=.2) cs2 = ax.contour(xx, yy, Z, cmap=ccolor, alpha=.6) ax.clabel(cs2, fmt = '%2.1f', colors = 'k', fontsize=14) and the errors are gone. However, a confirming reference would be helpful. -- Vicki Vicki Brown cfcl.com/vlb

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Request for help with a code
by Swayam Sahoo Oct. 26, 2019

Oct. 26, 2019

Hi , I am in need of a help to I want to curve fit with two independent variables: Tag and Tau . I tried inputting variables with tuple but it did not work. I would be grateful if you could assist me in this regard. Here is my code: import numpy as npimport matplotlib.pyplot as pltfrom scipy.optimize import curve_fit This is my model : def concentration(T,a,b,c,d): (Tag,Tau)=T return np.exp(a-d/Tag)/(np.exp(a-d/Tag) +np.exp(b-c/Tau)) Here I use a variable T which is a combination of two independent variables Tag and Tau. The output that I wish to fit is concentration. T=[(7.9481e-04,5.9061e-04), (7.64438e-04,6.1231e-04), (7.64438e-04,6.04905e-04), (7.85453e-04,6.01268e-04) ] experimental_concentration = [0.5428,0.798,0.75,0.70] many thanks, Swayam -- *Swayam Prakash Sahoo* Universität Stuttgart Germany

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Re: [Matplotlib-users] Animation examples
by edgar＠openmail.cc Oct. 22, 2019

Oct. 22, 2019

On 2019-10-18 14:06, Hannah wrote: > Hi, > I honestly don't know and I think this question needs to be posted to > the > mailing list at large. > Thanks, > Hannah > > On Fri, Oct 18, 2019 at 3:32 AM <edgar(a)openmail.cc> wrote: > >> What would you say about changing the policies from: >> >> We do not sell, trade, or otherwise transfer >> to outside parties your personally >> identifiable information. This does not >> include trusted third parties who assist us >> in operating our site, conducting our >> business, or servicing you, so long as those >> parties agree to keep this information >> confidential. We may also release your >> information when we believe release is >> appropriate to comply with the law, enforce >> our site policies, or protect ours or others >> rights, property, or safety. However, >> non-personally identifiable visitor >> information may be provided to other parties >> for marketing, advertising, or other uses. >> >> to something like this?: >> >> We do not sell, trade, or otherwise transfer >> to outside parties your personally >> identifiable information. We may release >> your information when we believe release is >> appropriate to comply with the law, enforce >> our site policies, or protect ours or others >> rights, property, or safety. >> >> Let me know. Thanks. >> >> >> On 2019-10-18 07:06, Hannah wrote: >> > Openly encouraging it as the Matplotlib team is trying to build it up >> > as a >> > community platform. It supports just about every type of registration >> > and >> > oauth, and we self host it on digital ocean. >>

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Re: [Matplotlib-users] Animation examples
by Paul Hobson Oct. 18, 2019

Oct. 18, 2019

Thanks, Edgar. Hopefully you find someone who will write the PR for you. The matplotlib development team is well aware of the differences between permissive licenses and copy-left licenses. On Thu, Oct 17, 2019 at 2:14 AM <edgar(a)openmail.cc> wrote: > Hi Paul, > > Thank you for your answer. I changed the license to BSD. I > don’t have a Github account, because I don’t want anything > to do with Micro$oft, G◉◉gle, etc. I leave this for the > uninformed: > > “The two major categories of free software license are > copyleft and non-copyleft. Copyleft licenses such as > the GNU GPL insist that modified versions of the > program must be free software as well. Non-copyleft > licenses do not insist on this. We recommend copyleft, > because it protects freedom for all users, but > non-copylefted software can still be free software, > and useful to the free software > community.”–[https://www.gnu.org/licenses/bsd.html] > > “…using a different license for your modifications > often makes that cooperation very difficult. You > should only do that when there is a strong reason to > justify it. > > One case where using a different license can be > justified is when you make major changes to a work > under a non-copyleft > > license.“–[https://www.gnu.org/licenses/license-recommendations.html] > > > On 2019-10-16 22:46, Paul Hobson wrote: > > Edgar, > > > > Thanks for sending these along. Matplotlib falls under a BSD license, > > so > > we'd need you to accept that before we could include them in the code > > base. > > > > The best way to get these into the code base is by submitting a PR on > > Github. We have a guide to contributing to matplotlib's development and > > documentation here: > > https://matplotlib.org/devdocs/devel/contributing.html > > > > Cheers, > > -Paul > > > > On Tue, Oct 15, 2019 at 1:00 AM <edgar(a)openmail.cc> wrote: > > > >> Hello, > >> > >> I would like to contribute with the following examples for animations. > >> Compared to some that I have found, they work with both dialogs and > >> saving a file (without phantom artists). > ... > >> but just it case, take GPL version 3. >

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Animation examples
by edgar＠openmail.cc Oct. 16, 2019

Oct. 16, 2019

Hello, I would like to contribute with the following examples for animations. Compared to some that I have found, they work with both dialogs and saving a file (without phantom artists). They do not redraw the whole canvas, but they do remove and recreate the original artist. I tested this on Parabola GNU/Linux 4.19.75-gnu-1-lts, Matplotlib 3.1.1, Python 3.7.4, qt5ct (Qt version 5.13.1). I don't know if a license is required, but just it case, take GPL version 3. ------------------------------------------------- This free account was provided by VFEmail.net - report spam to abuse(a)vfemail.net ONLY AT VFEmail! - Use our Metadata Mitigator to keep your email out of the NSA's hands! $24.95 ONETIME Lifetime accounts with Privacy Features! 15GB disk! No bandwidth quotas! Commercial and Bulk Mail Options!

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Bug with changing formatter and locator of a secondary axis ?
by Pierre Haessig Oct. 15, 2019

Oct. 15, 2019

Hello, I've a question on the secondary axis feature introduced in matplotlib 3.1 <https://matplotlib.org/3.1.1/users/whats_new.html#secondary-x-y-axis-support>. I'm on version 3.1.1. My use case is to plot log values but also display the exponentiated values. I can use a twin axes with the shared scale and a functional formatter. Here is an example: import numpy as np import matplotlib.pyplot as plt from matplotlib.ticker import LogLocator, FuncFormatter fig, ax = plt.subplots(1,1) # twin ax with shared scale # cf. @ImportanceOfBeingErnest at https://stackoverflow.com/questions/55907892/matplotlib-secondary-axis-with… ax2 = ax.twiny() ax.get_shared_x_axes().join(ax, ax2) # Plot ax.plot([-1,2,5], [1,2,3], 'd-') ax.grid() # x axis labeling ax.set_xlabel('log2 x-value') ax2.xaxis.set_major_formatter(FuncFormatter(lambda x,pos: f"{2**x:.3g}")) ax2.set_xlabel('x-value'); This twinx/y approach works, but I wanted originally to use the new secondary axis feature. I see to options for this: 1. use a secondary axes with the log transform 2. use a secondary axes with no transform, and then transform the display ticks using a FuncFormatter Option 1 works initially, but breaks when I want to use a LogLocator to have equally spaced log values: fig, ax = plt.subplots(1,1) ax.plot([-1,2,5], [1,2,3], 'd-') ax2 = ax.secondary_xaxis('top', functions=(lambda x: 2**x, np.log2)) # Place ticks at log equally spaced location [doesn't work] ax2.xaxis.set_major_locator(LogLocator(2)) Option 2 doesn't work either due. Setting the formatter has no effect fig, ax = plt.subplots(1,1) ax.plot([-1,2,5], [1,2,3], 'd-') ax2 = ax.secondary_xaxis('top') # Format the log values as exponentiated values [doesn't work] ax2.xaxis.set_major_formatter(FuncFormatter(lambda x,pos: f"{2**x:.3g}")) Is it an expected behavior (or a known bug) that changing the locator and the formatter of a secondary axis has no effect? Did I miss something? In the examples (https://matplotlib.org/3.1.1/gallery/subplots_axes_and_figures/secondary_ax…), there is one example (number 3, with interpolated transforms) which uses secax.xaxis.set_minor_locator(AutoMinorLocator()), but I don't know if it is effective or not. Best, Pierre

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Choosing a Backend
by Amit Yaron Oct. 3, 2019

Oct. 3, 2019

Gi, When I publish or send a Matplotlib script that uses 'gtk3agg' or 'tkagg', can I just be sure that the recipients can use the backend my script does?

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