PHP json_encode errors messages for JQuery

Question

I have the following method in my PHP class that processes messages and sends it back to JQuery. It works fine if there is only a single message to send back but if there is more than one, it sends them back as separate json objects. The messages are sent back ok but JQuery gives me an error. The messages look like this:

{"error":true,"msg":"Message 1 here..."}{"error":true,"msg":"Message 2 here"}

My PHP method looks like this:

private function responseMessage($bool, $msg) {
    $return['error'] = $bool;
    $return['msg'] = $msg;
    if (isset($_POST['plAjax']) && $_POST['plAjax'] == true) {
        echo json_encode($return);
    }
    ...
}

I don't know how to change this so multiple error messages are put into a single json encoded message but also work if it is just a single message.

Can you help? Thanks

Michael Berkowski · Accepted Answer · 2012-06-04 13:10:13Z

2

Looks like you need to be appending onto an array and then when all messages have been added, output the JSON. Currently, your function outputs JSON any time it is called:

// Array property to hold all messages
private $messages = array();

// Call $this->addMessage() to add a new messages
private function addMessage($bool, $msg) {
   // Append a new message onto the array
   $this->messages[] = array(
     'error' => $bool,
     'msg' => $msg
   );
}
// Finally, output the responseMessage() to dump out the complete JSON.
private function responseMessage() {
    if (isset($_POST['plAjax']) && $_POST['plAjax'] == true) {
        echo json_encode($this->messages);
    }
    ...
}

The output JSON will be an array of objects resembling:

 [{"error":true,"msg":"Message 1 here..."},{"error":true,"msg":"Message 2 here"}]

answered Jun 4, 2012 at 13:10

Michael Berkowski

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3 Comments

user1002039 Over a year ago

Thank you! I can try this and see.

user1002039 Over a year ago

Is it normal to always get the square bracket around the json object even if there is only one message?

Michael Berkowski Over a year ago

@user1002039 Since you made an array, yes. In your JavaScript code that receives this JSON, you'll need to access the first array element if you have only one.

Niet the Dark Absol · Accepted Answer · 2012-06-04 13:09:16Z

0

You can send the errors as an array.

$errors = Array();
// some code
$errors[] = ...; // create an error instead of directly outputting it
// more code
echo json_encode($errors);

This will result in something like:

[{"error":true,"msg":"Message 1 here..."},{"error":true,"msg":"Message 2 here"}]

answered Jun 4, 2012 at 13:09

Niet the Dark Absol

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Comments

Luc · Accepted Answer · 2012-06-04 13:10:56Z

0

Sounds like a design issue. You need to build up an object like $response = array(); and then every time an error needs to be added just append it. $response[] = $errorData; then when ur finished just json_encode($response);

answered Jun 4, 2012 at 13:10

Luc

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