Passing multiple arguments in Django custom command

Question

How do I enable a Django custom command to accept multiple arguments? Suppose that my command is to be called process_data, and in myproject/myapp/management/commands/process_data.py I have the following:

class Command(BaseCommand):
    def handle(self, *args, **options):
        alpha = args[0]
        beta = args[1]

And then call the command as follows:

>python manage.py process_data 5 16

I get the error:

manage.py: error: no such option: 16

This suggests that it sees my second argument 16 as part of **options, rather than a second argument in *args. How can I ensure that it is processed as an argument?

dukebody · Accepted Answer · 2014-10-26 09:38:41Z

1

You don't add options to the management command like this. Check the Django documentation about writing management commands.

Rewriting your example without testing it (it might have typos):

from optparse import make_option
class Command(BaseCommand):
    option_list = BaseCommand.option_list + (
        make_option('--alpha',
            action='store',
            dest='alpha'),
        make_option('--beta',
            action='store',
            dest='beta'),
        )

    def handle(self, *args, **options):
        alpha = options['alpha']:
        beta = options['beta']
        # ...

answered Oct 26, 2014 at 9:38

dukebody

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