Bash Linux Curl send headers from variable

Question

I have some script in bash. I want to send a request to server with some headers (cloudflare block :).

I wrote this:

headers="\
-H 'Host: somesite.com' \
-H 'Accept-Language: pl,en-US;q=0.7,en;q=0.3' \
-H 'Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8' \
-H 'User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:32.0) Gecko/20100101 Firefox/32.0' \
-H 'Accept-Encoding: gzip, deflate' \
-H 'DNT: 1' \
-H 'Connection: keep-alive'";

curl $headers somesite.com

But in output I'm have this..

curl: (6) Couldn't resolve host 'Accept-Language'
curl: (6) Couldn't resolve host 'pl,en-US;q=0.7,en;q=0.3'
curl: (6) Couldn't resolve host 'Accept'
curl: (6) Couldn't resolve host 'text'
curl: (6) Couldn't resolve host 'User-Agent'
curl: (6) Couldn't resolve host 'Mozilla'
curl: (6) Couldn't resolve host '(Windows'
curl: (6) Couldn't resolve host 'NT'
curl: (6) Couldn't resolve host '6.1;'

How can I put headers from variable into command ?

To add to @TomFenech, best practice is to quote a variable when it contains spaces. — Circadian
– Circadian, Commented Oct 26, 2014 at 20:12

Etan Reisner · Accepted Answer · 2014-10-26 20:09:47Z

1

Don't use a string for this. Trying to get quoting correct in a string like this is essentially impossible, use an array.

See http://mywiki.wooledge.org/BashFAQ/050 for more.

answered Oct 26, 2014 at 20:09

Etan Reisner

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