list1 = [2,4,5,6,7,89]
lambdafunction = lambda x: x > 20
print(any(lambdafunction(list1)))
I basically want it to print true or false on the condition x > 20 if any of the numbers in the list are greater than 20. How would I do that using an 'any' function and a lambda? I know how to check for a specific position in the list, but not how to check the whole list.
To keep it functional you could use map:
list1 = [2,4,5,6,7,89]
lambdafunction = lambda x: x > 20
print(any(map(lambdafunction, list1)))
map returns an iterator in python3 so the values will be lazily evaluated. If the first element in your lists is > 20, not more values will be consumed from the iterator.
In [1]: list1 = [25,4,5,6,7,89]
In [2]: lambdafunction = lambda x: x > 20
In [3]: it = map(lambdafunction, list1)
In [4]: any(it)
Out[4]: True
In [5]: list(it)
Out[5]: [False, False, False, False, True]
You can do:
>>> print(any(lambdafunction(x) for x in list1))
True
Or even:
>>> print(any(x > 20 for x in list1))
True
This iterates over the elements of the list and it checks that each element is greater than 20. The any() function takes care of returning the correct answer. In your solution you're not iterating over each element.
You could do something like this:
list1 = [2,4,5,6,7,89]
lambdafunction = lambda x: [item > 20 for item in x]
print(any(lambdafunction(list1)))
lambdafunction would return an array of booleans which would be if each element in the array is greater than 20. Then, you could use any to see if any of them are true.
But I would recommend using a regular function (using def) if possible.
lambdafunction = lambda x: (item > 20 for item in x)
any(x>20 for x in list1)