I have below string
ids = ["4,5,6"]
when I do
ids = ["4,5,6"].split(',')
Then I get ids as [["4,5,6"]]
can I do something to get ids as [4, 5, 6] ?
3 Answers
You're trying to split an array, try to split a string instead:
["4,5,6"].first.split(',')
#=> ["4", "5", "6"]
After that you can simply convert it to an array of ints:
["4", "5", "6"].map(&:to_i)
#=> [4, 5, 6]
Comments
There are many ways to do it. More generic version (if you expect more than one string in the original array e.g.: ["4,5,6", "1,2,3"]):
> ["4,5,6"].flat_map{ |i| i.split(',') }.map(&:to_i)
=> [4, 5, 6]
> ["4,5,6", "1,2,3"].flat_map{ |i| i.split(',') }.map(&:to_i)
=> [4, 5, 6, 1, 2, 3]
My answer appears to be less concise than the accepted one and I'm fairly new to Ruby. I think that you can use ! to alter the Array in place.
Problem: Original Array with 1 element as a String
ids=["4,5,6"];
Goal: Array with 3 elements of Integers
new_ids=[];
Process:
- Convert the Array to a String
- Create a new Array where each element is created by the comma ','
- Convert each element to an Integer
- Push each Integer Element to the Goal Array
new_ids.flatten.each do |i| new_ids.push(i.to_i) end;
Results: Display the New Integer Array
new_ids
[4, 5, 6]
2 Comments
Roland Studer
Good job, spelling out the steps. I recommend to get familiar with map and passing a method into an enumerator. There are often more direct approaches than with
.each, and you will see a lot of ruby code, you will not understand, if you do not now .map .inject .reduct and stuff like .map(&:to_i)
TheWind
Thank you @RolandStuder :-D
idscome from in the first place? I would understandids = ["4" ,"5", "6"]orids = "4,5,6"but that string within an array smells like a bug elsewhere.