Help parse XML to PHP by attribute value

Question

Could someone kindly help me get this parsed. I have the following XML. I need to get the value of photo-url that matches "75" max-width. How do I filter that in PHP $xml->posts->post['photo-url']....?

<photo-url max-width="100">
image1.jpg
</photo-url>

<photo-url max-width="75">
image2.jpg
</photo-url>

Yoshi · Accepted Answer · 2011-07-20 14:52:56Z

4

Using PHP DOM

$dom = new DomDocument;
$dom->loadXml('
<root>
    <photo-url max-width="100">image1.jpg</photo-url>
    <photo-url max-width="75">image2.jpg</photo-url>
</root>
');

$xpath = new DomXpath($dom);
foreach ($xpath->query('//photo-url[@max-width="75"]') as $photoUrlNode) {
    echo $photoUrlNode->nodeValue; // will be image2.jpg
}

answered Jul 20, 2011 at 14:52

Yoshi

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Comments

Michael Berkowski · Accepted Answer · 2011-07-20 14:58:34Z

3

Use SimpleXMLElement and an xpath query.

$xml = new SimpleXMLElement($your_xml_string);
$result = $xml->xpath('//photo-url[@max-width="75"]');

// Loop over all the <photo-url> nodes and dump their contents
foreach ($result as $node ) {
   print_r($node);
   $image = strip_tags($node->asXML);
}

edited Jul 20, 2011 at 14:58

answered Jul 20, 2011 at 14:52

Michael Berkowski

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1 Comment

anna Over a year ago

Woo, thanks! So my final usage was as following $img = $xml->xpath('//photo-url[@max-width="75"]'); echo '<img src="'.$img[0].'" />';

Kirill Polishchuk · Accepted Answer · 2011-07-20 14:53:04Z

1

You can use XPath: //photo-url[@max-width = '75']. It will select all photo-url which satisfies this condition. To select only 1st photo-url use this: //photo-url[@max-width = '75'][1]

answered Jul 20, 2011 at 14:53

Kirill Polishchuk

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