The question is odds([1, 2, 3, 4, 5, 6]) the output must be [1, 3, 5]. I know its simple in list comprehension, or a small function.
def odds(l):
r = []
for n in l:
if n % 2 == 1:
r.append(n)
return(r)```
or
def odds(l):
return [n for n in l if n % 2 == 1]
but i need the output using lambda function shown below
odds = lambda :
odds = lambda l: [x for x in l if x % 2 == 1]
Without list expression:
odds = lambda l: list(filter(lambda x:x%2==1, l))
But list expressions are the more pythonic solution always.
odds = lambda l: list(filter(lambda x:x%2==1, l))This stores a lambda function object in ans.
ans = lambda l: [i for i in l if i&1 == 1]
To use the function:
ans([1,2,3,4,5,6,7])
Output:
[1, 3, 5, 7]
odds = lambda _: list(filter(None, map(lambda x: x if x % 2 == 1 else None, _)))
Without using list comprehension I think there is no simpler way.
