How to concat additional string with the typescript type definition object?

Question

Let says I have a type as follows:

export enum configType {
  value = 'blah bala',
  value2 = 'blah bala',
  value3 = 'blah bala',
  value2 = 'blah bala',

}

Now I want to create a new type with above enum as follows:

export type analog = {
    [v + '_key' in configType]?: boolean;
}

Would this be possible?

jsejcksn · Accepted Answer · 2022-01-20 09:15:55Z

1

You can do this with literal types the type utilities Record<Keys, Type> and Partial<Type>.

TS Playground

enum ConfigType {
  Value = 'Value',
  Value2 = 'Value2',
  Value3 = 'Value3',
  Value4 = 'Value4',
}

type Analog = Partial<Record<`${ConfigType}_key`, boolean>>;

/*

type Analog = {
  Value_key?: boolean;
  Value2_key?: boolean;
  Value3_key?: boolean;
  Value4_key?: boolean;
}

*/

answered Jan 20, 2022 at 9:15

jsejcksn

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2 Comments

FR STAR Over a year ago

Can we also change the key-value type along with this? because currently key value is converted to any, but I need it as string.

jsejcksn Over a year ago

@FRSTAR If you have a new question, please ask a new question.

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