I have sth like that inside *.txt file.
function_name({"one": {"id": "id_for_one", "value": "value_for_one"}, ...});
And I am getting the file like this:
$source = 'FILE_NAME.txt';
$json = json_decode(file_get_contents($source),true);
echo $json['one']['value'];
It doesn't work, but when I remove function_name( and ); it works.
How to parse it without removing these strings?
You can't. It is not valid JSON with those. Take a substring that excludes them.
You will have to remove those strings. With the function_name portion it is not valid JSON.
A JSON string will typically either begin with { (object notation) or [ (array notation), but can also be scalar values such as a string or number. You cannot parse it without first making sure the string is valid JSON.
You are trying to get the string within a file and decoding it as a JSON file.
The 'function_name' isn't a valid JSON string, the rest inside yes.
How to parse it without removing these strings?
There is no way.
This should work for you.
$data = file_get_contents($source);
$data = substr($data, strlen("function_name("));
$data{strlen($data)-1}=$data{strlen($data)-2}=" ";
$json = json_decode($data,true);
Both {} and [] works for string to access individual characters.
The function in your text file, means that isn't a json file.
Remove the string using a regular expression, and your problem is fixed.
If the function is a fixed name, do something like this:
$source = 'FILE_NAME.txt';
$json_content = str_replace('function_name(', '', file_get_contents($source));
$json_content = substr($json_content,0,-2);
$json = json_decode($json_content,true);
echo $json['one']['value'];
function_name appears in JSON as well?