numpy.outer() function - Python
Last Updated :
05 May, 2020
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numpy.outer() function compute the outer product of two vectors.
Syntax : numpy.outer(a, b, out = None) Parameters : a : [array_like] First input vector. Input is flattened if not already 1-dimensional. b : [array_like] Second input vector. Input is flattened if not already 1-dimensional. out : [ndarray, optional] A location where the result is stored. Return : [ndarray] Returns the outer product of two vectors. out[i, j] = a[i] * b[j]Code #1 :
# Python program explaining
# numpy.outer() function
# importing numpy as geek
import numpy as geek
a = geek.ones(4)
b = geek.linspace(-1, 2, 4)
gfg = geek.outer(a, b)
print (gfg)
[[-1. 0. 1. 2.] [-1. 0. 1. 2.] [-1. 0. 1. 2.] [-1. 0. 1. 2.]]Code #2 :
# Python program explaining
# numpy.outer() function
# importing numpy as geek
import numpy as geek
a = geek.ones(5)
b = geek.linspace(-2, 2, 5)
gfg = geek.outer(a, b)
print (gfg)
[[-2. -1. 0. 1. 2.] [-2. -1. 0. 1. 2.] [-2. -1. 0. 1. 2.] [-2. -1. 0. 1. 2.] [-2. -1. 0. 1. 2.]]
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