Javascript Multidimensional Array/Hashtable

Question

storeChildren : function(coreid, data) {
  $.each(data, function(id, type) {
    $.core.children[coreid] = {};
    $.core.children[coreid]['id'] = id;
    $.core.children[coreid]['type'] = type;
  });
}

($.core.children is an object)

I want the resulting array/object (I prefer objects) to look like this (excuse my PHP pseudocode):

array(coreid => array(id=>type, id=>type, id=>type));

I know I am overwriting $.core.children[coreid] each time I run the loop I just don't know how to fix it.

I'd use an object instead var obj = { key: value, key: value, ... } — elclanrs
– elclanrs, Commented Apr 7, 2012 at 4:40

dfreeman · Accepted Answer · 2012-04-07 04:42:23Z

2

If all your 'id's are unique, the following should work; is this what you're after?

storeChildren : function(coreid, data) {
  $.core.children[coreid] = {};
  $.each(data, function(id, type) {
    $.core.children[coreid][id] = type;
  });
}

answered Apr 7, 2012 at 4:42

dfreeman

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Comments

jamesmortensen · Accepted Answer · 2012-04-07 04:45:16Z

0

init: function() {
    $.core.children = []; // instantiate array
},

storeChildren : function(coreid, data) {

    $.each(data, function(id, type) {
        $.core.children[coreid] = {id : type};
    });
}

Instantiate the object elsewhere in your code, then you won't kill the associative array/object each time. The above example also uses an object inside your array instead of an array, the result, in JSON notation, looks as follows:

[ {key,value} , {key,value} , {key,value} , ...]

The coreid is the index of the array.

answered Apr 7, 2012 at 4:45

jamesmortensen

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