javascript replace string and before chars of url

Question

i have following urls, which i want to find a string and remove that string and anything before it.

String: me.do?page=

URL can be

http://demo.com/me.do?page=/facebook/link/home.php
http://demo.com/sub-folder/me.do?page=/facebook/link/home.php
http://**subdomain**.demo.com/sub-folder/demo/me.do?page=/facebook/link/home.php

final output should be

/facebook/link/home.php
/facebook/link/home.php
/facebook/link/home.php

Russ · Accepted Answer · 2012-06-23 17:19:16Z

2

Don't really need regex even for this case:

var url = "http://demo.com/me.do?page=/facebook/link/home.php";
var result = url.split("/me.do?page=")[1];

answered Jun 23, 2012 at 17:19

Russ

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2 Comments

ajax333221 Over a year ago

note that if there is another "/me.do?page=" for some reason it will fail. To split and get everything after it even if the thing to split appears more than once this question will be useful

Russ Over a year ago

I should probably explain there's a few caveats to this code. One is that /me.do?page= has to exist in the string or split will return an array of 1 string and you will get an index out of bounds error from [1]. Second, like @ajax333221 said if there is more than 1 /me.do?page= it will (or should) only grab the result between the first and second instance. The other answers provided here are more robust in these manners, but this is a quick and dirty solution that's rather readable

Ashwin Singh · Accepted Answer · 2012-06-23 17:21:42Z

1

 var ur="http://demo.com/sub-folder/me.do?page=/facebook/link/home.php";
  var answer=ur.substring(ur.indexOf("me.do?page=")+11, ur.length);

answered Jun 23, 2012 at 17:21

Ashwin Singh

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1 Comment

Russ Over a year ago

1st if anyone is wondering where the +11 came from its the length of me.do?page=. 2nd the second parameter for substring() can be omitted to grab the rest of the string which is what ur.length does. This is more robust than my answer as it will find the first instance of me.do?page= and return the rest, but we have a 'magic number' dependent on the length of the string your searching for...

David Thomas · Accepted Answer · 2012-06-23 17:23:06Z

0

If you really feel you need a regex answer for this question, and bear in mind that string manipulation is faster/cheaper, there's:

var urls = ["http://demo.com/me.do?page=/facebook/link/home.php",
                    "http://demo.com/sub-folder/me.do?page=/facebook/link/home.php",
                    "http://**subdomain**.demo.com/sub-folder/demo/me.do?page=/facebook/link/home.php"],
    newUrls = [];

for (var i = 0, len = urls.length; i < len; i++) {
    var url = urls[i];
    newUrls.push(url.replace(/.+\/me\.do\?page\=/, ''));
}

console.log(newUrls);

JS Fiddle demo.

answered Jun 23, 2012 at 17:23

David Thomas

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