How to return objects as JSON objects from Python function?

Question

Here's my python module:

#!/usr/bin/python

import rpy2.robjects as robjects
import MySQLdb as mdb
import json
import rpy2.robjects.vectors as ro
r= robjects.r

class Deviation:
    def __init__(self):
        print("Standard Deviation")

    def s_deviation(self):
        con = mdb.connect('localhost', 'root', 'devil', 'data')        
        cursor = con.cursor()
        cursor.execute("SELECT * FROM traffic")
        rows = cursor.fetchall()
        rows = list(rows)
        a = [x[1] for x in rows]
        result = ro.IntVector(a)
        a = r.sd(result)
        print a

def deviation():
    dev = Deviation()
    deviation = dev.s_deviation()

The function deviation() from this module when called returns the result as R vector. How do I make this return the result as Json objects? Thank you!

None of your functions return anything.

halex
– halex

2012-08-29 08:36:39 +00:00
Commented Aug 29, 2012 at 8:36 — halex
– halex, Commented Aug 29, 2012 at 8:36

Michael Anderson · Accepted Answer · 2012-08-29 08:47:14Z

1

Use json.dumps or simplejson.dumps (depending on your python version). You use it like this:

>> print( simplejson.dumps( { "dev": dev.s_deviation() } ) )
'{"dev":1.456}'

answered Aug 29, 2012 at 8:47

Michael Anderson

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