Creating a namespace object from string to call a function?

Question

i have a namespace object form.iso.methodName as a string and i want to call that method. I cant create namespace object like [form][iso][methodName]

split : function(ns) { // ns namespace is object
    var splitNameSpace = ns.split('.');
    var methodName = splitNameSpace.pop();
    //console.log(splitNameSpace);
    var content = [];

    for (var i=0;i<splitNameSpace.length;i++){
        content = [splitNameSpace[i]];
        console.log(content);
    }

*Update- Found solution *

split : function(ns) {
    var splitNameSpace = ns.split('.');
    var methodName = splitNameSpace.pop();
    //console.log(splitNameSpace);
    var content = [];
    var obj;
    for (var i=0;i<splitNameSpace.length;i++){
        obj = [splitNameSpace[i]];
    content = content+"["+obj+"]";

    }

@AndrewMcGivery i am passing a namespace string in function split parameter and i want that function to split up and build namespace object [form][iso[methodName] so i can call a function which is in different namespace object.. i hope i explained .i am bad at english — inputError
– inputError, Commented Mar 2, 2013 at 3:00
So, if I'm to understand, you want to call form.iso.methodName() given the string "form.iso.methodName"? — Andrew McGivery
– Andrew McGivery, Commented Mar 2, 2013 at 3:03

elmasse · Accepted Answer · 2013-03-02 03:20:36Z

2

You can do this:

function namespace(ns){
    var d, o;
    n = ns.split('.');
    o = window[n[0]] = window[n[0]] || {};
    var l = n.length;
    for(var i=1; i<l; i++){
        o = o[n[i]] = o[n[i]] || {};
    }
    return o;
}

 var param = 'foo.bar.blah.methodName',
     method = param.split('.').pop(),
     ns = param.split('.').slice(0,-1).join('.'),
     obj = namespace(ns); 

 obj[method]();

You can improve this by retrieving the global object instead of using window

edited Mar 2, 2013 at 3:20

answered Mar 2, 2013 at 3:03

elmasse

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4 Comments

inputError Over a year ago

i cant get it and i am trying to pop the last ns after split for method name and the rest as namespace object but i dont understand what you are doing?

elmasse Over a year ago

You can call namespace to retrieve the namespace of your method:

var param = 'foo.bar.blah.methodName'; method = ns.split('.').pop(); ns = param.split('.').slice(0,-1).join('.'); obj = namespace(ns); obj[method]();

inputError Over a year ago

i found out the solution bit untidy but works

split : function(ns) { 		var splitNameSpace = ns.split('.'); 		var methodName = splitNameSpace.pop(); 		//console.log(splitNameSpace); 		var content = []; 		var obj; 		for (var i=0;i<splitNameSpace.length;i++){ 			obj = [splitNameSpace[i]]; 			//console.log(obj); 			content = content+"["+obj+"]"; 			//var	cont = content[splitNameSpace[i]]; 			//content = cont; 			//cont = content[i]; 			//console.log(content); 			//console.log(methodName); 		}

stot Over a year ago

wow - exactly what i needed and it works! One comment: in function namespace the variable d is not used.

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