How to put css selectors into php generated html code

Question

I'm trying to make one little prototype on PHP and Wordpress, and I can't find out what is wrong with this.

This code is fine:

<?php
    mysql_connect( "localhost", "root");
    mysql_select_db( "wp");
                  
    $result = mysql_query("select score from test"); 
    $argument = mysql_query("select level from test");
    echo "<table>\n";
    echo "<tfoot><tr>\n";
    while ($myarg = mysql_fetch_row($argument))
    {
    printf("<th>%s</th>\n", $myarg[0]);
    }
    echo "</tr></tfoot>\n";
    echo "<tbody><tr>\n";
    while ($myres = mysql_fetch_row($result))
    {
    printf("<td>%s</td>\n", $myres[0]);
    }
    echo "</tr></tbody>\n";
    echo "</table>\n";  
?>

But when I add selector to table, like this:

echo "<table id="data">\n";

I've got the following error on the page:

Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in ... ...

Same thing when I add styles.

Your title is totally misleading...? "How to put css selectors into php generated html code" should be something like "unexpected T_STRING" or "Error including id into table in a string" etc... — bestprogrammerintheworld
– bestprogrammerintheworld, Commented May 12, 2013 at 17:58

totymedli · Accepted Answer · 2013-05-12 18:00:40Z

The problem

The problem is that you try to print a character that has a meaning in the PHP language. You try to print a double quote but in this case it means end of the string (that you started with the first double quote) for the praser.

Solution

Use single quotes for echo:

echo '<table id="data">\n';

Escape the special character you want to print:

echo "<table id=\"data\">\n";

Explanation

You got a prase error because when the praser arrives at the end of echo "<table id=" part, it expects a ; as a close for your command or a comma with other parameters. That is the reason why it says:

Parse error: syntax error, unexpected T_STRING, expecting ',' or ';'

Also it says he got a T_STRING (instead of the expected values explained previously) that is the data you typed.
Furthermore the error message says that he is a syntax error. So it has a problem with what you typed, you used the wrong syntax.

Conclusion

Analyse your error messages, the praser gives them to help you to solve your problem. Also copying the error message to an online search engine can solve you a problem incredibly fast.

chandresh_cool · Accepted Answer · 2013-05-12 17:36:17Z

3

Use single quotes instead like this

echo "<table id='data'>\n";

answered May 12, 2013 at 17:36

chandresh_cool

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Comments

Tamil Selvan C · Accepted Answer · 2013-05-12 17:36:36Z

2

Try, use single quotes

echo "<table id='data'>\n";

answered May 12, 2013 at 17:36

Tamil Selvan C

20.3k12 gold badges55 silver badges72 bronze badges

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