Replacing string with variables stored in an array

Question

OK so i'm unsure with my syntax on this one, I do think the logic is self explanatory but I'm unsure if preg_replace will work or whether a loop is needed to get an end result.

$string = $randomizer->fecthRandomPhrase($cfg['seo']['meta']['descriptions']['single'], 3, $_SERVER['REQUEST_URI']);

Returns a string like this

Lorem ipsum dolor sit amet,[address1], [address2], [postcode]. consectetur adipiscing elit. Mauris id dui sem, eget laoreet tellus. Vivamus lacinia vestibulum odio a lobortis - [region]

I then search the string for the parts I want to change;

$find = array('[address1]','[address2]','[postcode]','[region]');

I then pull information stored in these variables and place them in an array;

$replace = array($ADDRESS1,$ADDRESS2,$POSTCODE,$region);

The before returning the phrase I apply a preg_replace to swap over the info I have stored

$phrase = preg_replace($find,$replace,$string);

Do I need to loop through the array $replace to allow the reading of each variable and for the replace to work or am I using the wrong function entirely?

Thanks for tidying that up Antony, I knew there would be a spelling mistake or missing code block somehow. (flux on screen makes it harder to see the grey boxes lol) — benf2489
– benf2489, Commented May 14, 2013 at 16:23

nickb · Accepted Answer · 2013-05-14 16:15:10Z

2

str_replace() can take arrays as its first two parameters, you might want to consider that instead. Otherwise, you'd need to form a proper regex for $find in order to only invoke preg_replace() once, which you currently are not doing.

Usage:

$phrase = str_replace( $find, $replace, $string);

Now $phrase shoud contain your desired output.

answered May 14, 2013 at 16:15

nickb

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benf2489 Over a year ago

Ah! Thanks for that i'll make sure to use str_replace when passing arrays this did the trick. Thanks nickb

chandresh_cool · Accepted Answer · 2013-05-14 16:15:18Z

2

use PHP's str_replace function like this

str_replace(array($your_replacement_array), array($your_replace_array), $string);

Hence what you want is this

str_replace(array('[address1]','[address2]','[postcode]',['region']), array($ADDRESS1,$ADDRESS2,$POSTCODE,$region), $string);

answered May 14, 2013 at 16:15

chandresh_cool

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Comments

2 revs · Accepted Answer · 2013-05-15 22:41:32Z

0

strtr is also useful.

On the following situation, only strtr works exptectedly.

$text = 'SonyEricsson is based in British, but Sony is based in Japan';

str_replace

code:

$search  = array(
    'SonyEricsson',
    'Sony',
);
$replace = array(
    '<a href="http://www.SonyEricsson.com">SonyEricsson</a>',
    '<a href="http://www.Sony.com">Sony</a>',
);
echo str_replace($search,$replace,$text);

result:

<a href="http://www.<a href="http://www.Sony.com">Sony</a>Ericsson.com"><a href="http://www.Sony.com">Sony</a>Ericsson</a> is based in British, but <a href="http://www.Sony.com">Sony</a> is based in Japan

strtr

code:

$replace_pairs = array(
    'SonyEricsson' => '<a href="http://www.SonyEricsson.com">SonyEricsson</a>',
    'Sony'         => '<a href="http://www.Sony.com">Sony</a>',
);
echo strtr($text,$replace_pairs);

result:

<a href="http://www.SonyeEricsson.com">SonyEricsson</a> is based in British, but <a href="http://www.Sony.com">Sony</a> is based in Japan

edited May 15, 2013 at 22:41

community wiki

2 revs
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2 Comments

benf2489 Over a year ago

I'll try to work this method with my next task as the next group of variables I need to replace are 3d arrays, I'm needing to replace more than once piece of information about a building such as the case with my example in the question I assume it would be easier to find all of the text I need to replace rather than splitting it up into multiple variables?

mpyw Over a year ago

Are you meaning that sending paired arguments like strtr is superior to sending splitted arguments like str_replace?

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