PHP set object properties dynamically [closed]

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I have a function, that should read array and dynamically set object properties.

class A {
    public $a;
    public $b;

    function set($array){
        foreach ($array as $key => $value){
            if ( property_exists ( $this , $key ) ){
                $this->{$key} = $value;
            }
        }
    }
}

$a = new A();
$val = Array( "a" => "this should be set to property", "b" => "and this also");
$a->set($val);

Well, obviously it doesn't work, is there a way to do this?

EDIT

It seems that nothing is wrong with this code, the question should be closed

Remove brackets {} and will work! -> $this->$key = $value; — Dimitris Bouzikas
– Dimitris Bouzikas, Commented Jan 24, 2014 at 15:50
yea, i just noticed, sorry guys, i made a mistake before setting stuff in the code — Ben
– Ben, Commented Jan 24, 2014 at 15:55

Dimitris Bouzikas · Accepted Answer · 2014-01-24 15:53:06Z

50

You only need to remove brackets {} and will work! -> $this->$key = $value;

answered Jan 24, 2014 at 15:53

Dimitris Bouzikas

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1 Comment

mickmackusa Mar 10 at 4:12

This answer is misleading. Adding the curly braces was been valid since PHP5.0 3v4l.org/MG7e1

Andrey · Accepted Answer · 2015-08-12 15:33:52Z

15

http://www.php.net/manual/en/reflectionproperty.setvalue.php

You can using Reflection, I think.

<?php 

function set(array $array) {
  $refl = new ReflectionClass($this);

  foreach ($array as $propertyToSet => $value) {
    $property = $refl->getProperty($propertyToSet);

    if ($property instanceof ReflectionProperty) {
      $property->setValue($this, $value);
    }
  }
}

$a = new A();

$a->set(
  array(
    'a' => 'foo', 
    'b' => 'bar'
  )
);

var_dump($a);

Outputs:

object(A)[1]
  public 'a' => string 'foo' (length=3)
  public 'b' => string 'bar' (length=3)

edited Aug 12, 2015 at 15:33

answered Jan 24, 2014 at 15:52

Andrey

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2 Comments

eis Over a year ago

you can, but why use it if simple setter will do

Ben Over a year ago

Answered, because posted something usefull

David Fiaty · Accepted Answer · 2021-03-10 11:11:30Z

1

It is to note that Reflection is not recommended in production mode. Depending on the context this one liner can do the job:

    $object = json_decode(json_encode($array));

answered Mar 10, 2021 at 11:11

David Fiaty

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