Django REST framework, get object from URL

Question

I'm wondering if there is a clean way to retrieve an object from its URL with django rest framework. Surely there should be, as it seems to be what's happening when using HyperlinkedRelatedField.

For instance, I have this URL /api/comment/26 as a string. From my view, how can I get the comment instance with pk=26?

Of course I could redo the work and work on the string but it must be a better way?

Thanks a lot.

EDIT:

This is how I solved it at the end:

resolve('/api/comment/26/').func.cls.model will return my model Comment. resolve('/api/category/1/').kwargs['pk'] will return the pk.

Which gives you:

from django.core.urlresolvers import resolve

resolved_func, unused_args, resolved_kwargs = resolve('/api/category/1/')
resolved_func.cls.model.objects.get(pk=resolved_kwargs['pk'])

Remember that if you have a fully qualified URL (e.g. starting with "http...") you need to extract its path and pass that to resolve. This can be done with the urlparse module. — Christoffer
– Christoffer, Commented Jul 6, 2015 at 18:52
I didn't look into it to much but for me resolved_func.cls returns the view set so I needed to use the following to get to the model: resolved_func.cls.serializer_class.Meta.model.objects.get(pk=resolved_kwargs['pk']) — Semprini
– Semprini, Commented Nov 24, 2015 at 1:32

Community · Accepted Answer · 2017-05-23 12:17:33Z

3

I suspect your best bet would be to manually keep a map of models to url patterns — not too dissimilar from a URLConf.

If that doesn't rock your boat you could pass the path into resolve.

This will give you a ResolverMatch upon which you'll find the func that was returned by the as_view call when you set up your URLs.

The __name__ attribute of your view function will be that of your original view class. Do something like globals()[class_name] to get the class itself.

From there access the model attribute.

I hope that helps. As I say, you might just want to map models to URLs yourself.

edited May 23, 2017 at 12:17

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answered Feb 13, 2014 at 15:49

Carlton Gibson

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2 Comments

Vincent Alvo Over a year ago

Thanks for your help!!! Nearly there, I tweaked a bit your answer to get exactly want I needed that way: resolve('/api/category/1/').func.cls.model

Carlton Gibson Over a year ago

Ah, ...func.cls is there is it? — Never needed it but that's much cleaner. Thank you to you too!

piro · Accepted Answer · 2016-02-26 18:29:04Z

2

With class-based views, something like the following seems needed:

resolve(url).func.cls.serializer_class.Meta.model.objects.get(
    **resolve(url).kwargs)

answered Feb 26, 2016 at 18:29

piro

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Pinna_be · Accepted Answer · 2018-02-21 11:22:55Z

0

Solution above did not work for me, the following did work though:

from django.core.urlresolvers import resolve

resolved_func, unused_args, resolved_kwargs = resolve('/api/category/1/')
resolved_func.cls().get_queryset().get(id=resolved_kwargs['pk'])

additionally this solution uses the built in queryset of your view, which might have annotations or important filters.

Using HyperlinkedModelSerializer I actually needed to do this with a full url. For this to work, you need to extract the path first, resulting in:

import urllib.parse
from django.core.urlresolvers import resolve

def obj_from_url(url):
    path = urllib.parse.urlparse(url).path
    resolved_func, unused_args, resolved_kwargs = resolve(path)
    return resolved_func.cls().get_queryset().get(id=resolved_kwargs['pk'])

answered Feb 21, 2018 at 11:22

Pinna_be

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1 Comment

EMiDU Over a year ago

django.core.urlresolvers module has been removed in Django 2.0 and url-related functions (like resolve) has been moved to django.urls: docs.djangoproject.com/en/3.0/ref/urlresolvers/#resolve

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