java split string into array by a few charaters

Question

got a string that looks like this:

"abc", "def", "ghi"

I need to split string to array like this:

abc
def
ghi

I tried:

String [] strArray = sb.toString().split(" ,\"");

but it doesn't work.

"it doesn't work" and your example doesn't make much sense... could you rephrase yourself please? — tanishalfelven
– tanishalfelven, Commented Oct 5, 2014 at 6:15

Zaheer Ahmed · Accepted Answer · 2014-10-05 06:30:49Z

1

You firstly need to remove first and last quotation from string:

sb = sb.substring(1, sb.length() - 1); //remove first and last character

after above line of code your sb will be:

abc", "def", "ghi

and then try this regex:

String[] strArray = sb.split("\"\\s*,\\s*\"");

its split on the basis of quote (any no of space) comma (any no of space) quote

answered Oct 5, 2014 at 6:30

Zaheer Ahmed

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Comments

venergiac · Accepted Answer · 2014-10-05 06:46:07Z

0

the split method accept regex

consider the following code

str.split("(\", \")+|(\")+")

you will get a four elements array

[, abc, def, ghi]

As suggested by Zaheer you can remove the first "

answered Oct 5, 2014 at 6:26

venergiac

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