Calling lambda functions with iteration over a numpy array of shape `(n,)`

Question

Let's define a function f such that f = lambda x1,x2, ... , xn: x1 + x2 and an numpy array a = np.array([a1,a2, ... , an]) of length n. How can I apply f using as arguments the components of a by iterating over every element of it?

Notice that I don't want to apply f this way: y = f(a[0], .... a[n]) but using a for loop (something like this: y = lambda(u for u in a)).

Do you want to do f(*a)?

BrenBarn
– BrenBarn

2014-12-17 19:01:21 +00:00
Commented Dec 17, 2014 at 19:01 — BrenBarn
– BrenBarn, Commented Dec 17, 2014 at 19:01

wim · Accepted Answer · 2014-12-17 23:20:10Z

2

You want the splat unpack trick:

>>> a = np.array(['hello ', 'world', 'blah', 'blah', 'blah'])
>>> f = lambda *args: args[0] + args[1]
>>> f(*a)
'hello world'

answered Dec 17, 2014 at 23:20

wim

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