php unset multidimensional array element which key value is match

Question

I have one multidimensional array:

Array
(
    [0] => stdClass Object
        (
            [user_type] => U
            [user_id] => 156
            [property_id] => 1201
        )

    [1] => stdClass Object
        (
            [user_type] => U
            [user_id] => 156
            [property_id] => 1200
        )

    [2] => stdClass Object
        (
            [user_type] => U
            [user_id] => 156
            [property_id] => 1196
        )

    [3] => stdClass Object
        (
            [user_type] => U
            [user_id] => 156
            [property_id] => 1193
        )
)

and I want to remove array which values are match with property_id:

Array
(
    [0] => 1201
    [1] => 1200
    [2] => 1193
)

and I want this result:

Array
(
    [0] => stdClass Object
        (
            [user_type] => U
            [user_id] => 156
            [property_id] => 1196
        )
)

I am sharing my code for what i have done:

for($b=0; $b<count($beBounceResults); $b++){
    $beBounceProID[] = $beBounceResults[$b]->property_id;
}
// Getting thus array in this variable $beBounceProID
Array
(
    [0] => 1201
    [1] => 1200
    [2] => 1193
)

$counter = "0";
foreach ($results as $key => $value){
    if($results[$key]->property_id == $beBounceProID[$counter]){
        unset($results[$key]);
    }
    $counter++;
}

but after that I am getting Notice: Undefined offset:

Any idea what I am doing wrong.

Thanks.

@anantkumarsingh This makes no difference! Absolutely wrong, if it 's index 0 it will cast it implicit to an int — Rizier123
– Rizier123, Commented Apr 8, 2015 at 8:26

SNAG · Accepted Answer · 2015-04-08 08:29:37Z

5

try this

foreach ($results as $key => $value){
    if(in_array($results[$key]->property_id , $beBounceProID) )
    {
        unset($results[$key]);
    }
}

answered Apr 8, 2015 at 8:29

SNAG

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1 Comment

Duenna Over a year ago

Fast and simple to understand +1

Rizier123 · Accepted Answer · 2015-04-08 08:33:53Z

2

Another approach is just to filter the arrays which you don't want out like this:

$arr = array_filter($arr, function($v)use($property_id){
    return !in_array($v->property_id, $property_id);
});

answered Apr 8, 2015 at 8:33

Rizier123

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