2

Code:

var str = '/tip -a 20 send 20tips to   chinu';
var parts = str.match(/^\/(\S+)\s+(\S+)\s+(\S+)\s*(.*)/).slice(1);
console.log(parts);

Output:

["tip", "-a", "20", "send 20tips to   chinu"]

I want to change the text :

var str = '/tip 20 send 20tips to   chinu';

The result should be ["tip", "20", "send 20tips to chinu"] but i am getting ["tip", "20", "send", "20tips to chinu"]

Please help me.

EDIT:

variable str contains dynamic text. It may be /tip 20 or /tip -a 20 check http://myshowcam.com/NewSite/chat-room/chinu type /help command you will get /tip command instructions.

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  • 2
    Again: TIP or PRICE? Commented May 5, 2015 at 7:23
  • its tip. Yesterday I was posting same question. but not getting any satisfied answer. Commented May 5, 2015 at 7:25
  • If it's dynamic, then you should not use (\S+)\s+(\S+)\s+(\S+)\s. So, by default, it matches three words Commented May 5, 2015 at 7:25
  • Because you were not giving the full story. Please refrain from posting the same question again, instead add information to your original question Commented May 5, 2015 at 7:25
  • In this code "/tip -a 20 send 20tips to chinu" you have 3 "single" words before "send 20tips to chinu", in this one "/tip 20 send 20tips to chinu", you have only 2 "words", the "-a" is missing. So the output is correct. Checkout this here regex101.com Commented May 5, 2015 at 7:27

3 Answers 3

Reset to default
1

You can use this regex with optional 2nd part with filter(Boolean):

// case 1
var str = '/tip -a 20 send 20tips to   chinu';
var parts = 
 (str.match(/^\/(tip)\s+(-[apm]\s+)?(\S+)\s*(.*)/) || ['tip', 'tip']).
      filter(Boolean).slice(1);
//=> ["tip", "-a ", "20", "send 20tips to   chinu"]

// case 2
str = '/tip 20 send 20tips to   chinu';
parts = 
 (str.match(/^\/(tip)\s+(-[apm]\s+)?(\S+)\s*(.*)/) || ['tip', 'tip']).
      filter(Boolean).slice(1);
//=> ["tip", "20", "send 20tips to   chinu"]

// case 3
str = '/tip';
parts = 
 (str.match(/^\/(tip)\s+(-[apm]\s+)?(\S+)\s*(.*)/) || ['tip', 'tip']).
      filter(Boolean).slice(1);
//=> ["tip"]
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9 Comments

var newStr = str.match(/^\/(\S+)\s+(-[apm]\s+)?(\S+)\s*(.*)/).filter(Boolean).slice(1); I have just modified your code. Now I am typing only /tip without any price, type and message. Still I am getting error.
I am using above input string which you have written. If i am entering only /tip i want to validate. I have used your code. But i am getting TypeError: str.match(...) is null error
You are right. But i was saying to validate. This is a text field. User may put any word. So i need to validate. If there is no word after /tip it says Error: Enter your tips amount if there are /tip -a it says Error: please enter valid number. I have tried yesterday. Unable to complete. I am very week in regular expression. Please help me. Thanks
My tips format is - /tip [optional -a,-p,-m] 20 [optional_comments] or /tip 20 [optional_comments]
Yes starting with /tip in other case it will change. Please check myshowcam.com/NewSite/chat-room/chinu type /help you will able to see the commands
|
1 

    var str1 = '/tip -a 20 send 20tips to   chinu';
    var str2 = '/tip 20 send 20tips to   chinu';
    var str3 = '/tip 20';
    
    function getArr(str) {
        if (str.split(" ")[1].indexOf("-")==0) return str.match(/^\/(\S+)\s+(\S+)\s+(\S+)\s*(.*)/).slice(1);
        else return str.match(/^\/(\S+)\s+(\S+)\s*(.*)/).slice(1);
    }
    alert(getArr(str1))
    alert(getArr(str2))
    alert(getArr(str3))

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5 Comments

Hi, Your code is working fine. But I am getting error when type only /tip If I will typing /tip it will saying Error: Please enter tips amount
Error - TypeError: str.split(...)[1] is undefined if (str.split(" ")[1].indexOf("-")==0) return str.match(/^\/(\S+)\s+(\S+)\s+(\S+...
Two cases this is not working 1st /tip and 2nd are /tip -any_word
They work. try test. If the strings are wrong, give me more examples
I do not understand what you enter to get errors. It should not be possible to enter /tip only - it must be followed by an amount. no?
0

You can use the following if your dynamic text always contains - before optional switch

^\/(\S+)\s+(-\S+)?\s*(\S+)\s*(.*)
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