Typescript - Overloading private method

Question

Hello I would like to achieve this scenario:

class A implements InterfaceForA
{
    a():void
    {
        this.b();
    }
}

Class B extends A
{
    private b():void
    {
        console.log('Hi');
    }
}

But it throws:

error TS2339: Property 'b' does not exist on type 'A'.

So I updated my class and now it throws:

error TS2415: Class 'B' incorrectly extends base class 'A'. Types have separate declarations of a private property 'b'.

With code:

class A implements InterfaceForA
{
    a():void
    {
        this.b();
    }

    private b():void
    {
        console.log('Hello');
    }
}

Class B extends A
{
    private b():void
    {
        console.log('Hi');
    }
}

In C++, I would set in class A method b() as virtual private, and problem would be solved. In JS it wouldn't be problem at all. How to do it in TypeScript?

Community · Accepted Answer · 2017-05-23 12:30:49Z

10

In C++ you would actually set it as protected. Private members are private.

Typescript >= 1.3 supports protected qualifier.

See: What is the equivalent of protected in TypeScript?

edited May 23, 2017 at 12:30

CommunityBot

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answered Jun 22, 2015 at 6:47

Andrei Tătar

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2 Comments

Anton Piliak Over a year ago

In C++, 'private virtual' differs from protected. It can be overridden, but cannot be called from derived class.

Andrei Tătar Over a year ago

@AntonPilyak Thanks! Good to know.

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