PHP multiple variables

Question

I am learning some php right now. Is there a way to define a variable with multiple variables?

Something like:

$name = "John"
$lastname = "Doe"
$number = "017434234"

$user = $name,$lastname,$number

Of corse this script does not work. Which is the correct way?

As an array? $user = [$name,$lastname,$number]; var_dump($user);? — Mark Baker
– Mark Baker, Commented Sep 2, 2015 at 9:57
Depends, what are you trying to do? Defining a variable with multiple variables does not mean much. You want to concatenate them? Create an array? — Eloims
– Eloims, Commented Sep 2, 2015 at 9:59
add semicolon at the end of variable deceleration and concate them using $user = $name.",".$lastname.",".$number; — Saty
– Saty, Commented Sep 2, 2015 at 9:59
Are you learning PHP, or are you learning programming at all? Because you should have a basic knowledge of programming structures. Like arrays. — Amarnasan
– Amarnasan, Commented Sep 2, 2015 at 10:01

BobbyTables · Accepted Answer · 2015-09-02 10:00:10Z

1

If you want to put them together, the dot concatenates the variables:

$user = $name.$lastname.$number;

If you want to define multiple strings, you can use an array:

$user = ["John", "Doe", "123"];

Or you can use keys in your array to give them meaning:

$user = [firstname => "John", lastname => "Doe"];
echo $user->firstname; //gives John

edited Sep 2, 2015 at 10:00

answered Sep 2, 2015 at 9:59

BobbyTables

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2 Comments

user3782541 Over a year ago

Thanks a lot! That was quite easy :-)

CD001 Over a year ago

... or build a User class instead of an associative array for structured objects

MrK · Accepted Answer · 2015-09-02 10:12:20Z

0

Awesome that youre learning PHP :)

You can make it an array like this whit a function, of course.. this is a little more "over complicated" than the example above.

Script:

//Function array with inputting and selecting what to return:
function MyArray($Firstname, $Lastname, $Number, $OutPutWhat){

   //Create an array:
   $Array = array(
       'FirstName' => "$Firstname",
       'LastName' => "$Lastname",
       'Number' => "$Number"
   );
       //Return the arrayValue[ofthis]
       return $Array[$OutPutWhat];
}

 //Echo out the value
echo MyArray("John", "Doe", "1234567", 'FirstName');  //Outputs the firstname

answered Sep 2, 2015 at 10:12

MrK

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