Compare two objects in an array using jquery and insert the missing element

Question

I am having multiple objects in an array i want to make the element in each object same

var objectArray = [obj1,obj2,obj3.........]

obj1 ={
2002-Edad 15 a 64 años: 0.1854095,
2003-Edad 15 a 64 años: 0.1531632,
2005-Edad 15 a 64 años: 0.1887739,
2006-Edad 15 a 64 años: 0.1754043,
2007-Edad 15 a 64 años: 0.2038664,
2008-Edad 15 a 64 años: 0.2270297,
2009-Edad 15 a 64 años: 0.211827,
2011-Edad 15 a 64 años: 0.2396887,
2012-Edad 15 a 64 años: 0.2618066,
2013-Edad 15 a 64 años: 0.2677819,
var_descripcion: "Asalariados con contrato a término fijo (en %)"}

obj2 ={
2002-Edad 15 a 64 años: 0.1854095,
2003-Edad 15 a 64 años: 0.1531632,
2005-Edad 15 a 64 años: 0.1887739,
2006-Edad 15 a 64 años: 0.1754043,
2007-Edad 15 a 64 años: 0.2038664,
2011-Edad 15 a 64 años: 0.2396887,
2012-Edad 15 a 64 años: 0.2618066,
2013-Edad 15 a 64 años: 0.2677819,
var_descripcion: "Asalariados con contrato a término fijo (en %)"}

I want to compare this arrays and insert the missing value in second arrays ie,

2008-Edad 15 a 64 años: 0.2270297 & 2009-Edad 15 a 64 años: 0.211827

but value as 0

In this way I want to make all the objects in array similar

Please help;

Zac Braddy · Accepted Answer · 2015-11-13 11:05:44Z

1

Here is an example of how you could do that. You will find that after having executed normalizeArray on the test array that the second object in the array will have the "second" property initialized to 0. Here's a fiddle of it working.

function mergeObject(from, to) {
  for(var prop in from) {
    if (typeof(to[prop]) === 'undefined') {
      to[prop] = 0;
    }
  }

  return to;
}

function normalizeArray(arr) {
  var schema = {};
  for(var i = 0; i < arr.length; i++) {
    schema = mergeObject(arr[i], schema);
  }

  for(var i = 0; i < arr.length; i++) {
    arr[i] = mergeObject(schema, arr[i]);
  }
}

var test1 = {
  first: 1,
  second: 2,
  third: 3
}

var test2 = {
  first: 1,
  third: 3
}

var testArray = [test1, test2];

normalizeArray(testArray);

edited Nov 13, 2015 at 11:05

answered Nov 13, 2015 at 10:55

Zac Braddy

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Comments

CiaranSynnott · Accepted Answer · 2015-11-13 10:48:04Z

0

Simply compare the arrays;

            var array1 = [1,2,3,4,5],
                array2 = [5,4,3,2,1],
                array3 = [1,2,,6,7,8];

            function compareArrays(arr1, arr2) {
                return $(arr1).not(arr2).length == 0 && $(arr2).not(arr1).length == 0
            };

answered Nov 13, 2015 at 10:48

CiaranSynnott

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