PHP: Direct access to an element in an array of objects

Question

I am trying to output a set of data, and I have, due to my LEFT OUTER JOIN got multiple rows per match.

I'm using a positive look ahead to see if the next row is the same id as the first. However the return from the database class returns an array of objects.

array(7) {
          [0]=> object(stdClass)#4 (8) {
                                      ["dom_id"]=>string(1) "3"
                                      ["domain"]=>string(11) "example.com"
                                      ["status"]=>string(7) "Invalid"
                                      ["expiry"]=>string(10) "2010-07-20"
                                      ["remaining"]=>string(6) "0 Days"
                                      ["rem_id"]=>NULL
                                      ["alert_type"]=>NULL
                                      ["contact"]=>NULL
  }
//etc

I am getting the following error, Fatal error: Cannot use object of type stdClass as array

My code is as follows,

echo $domains[$k+1]->alert_type;

I know that I could assign the new dimension to a variable and access that as an object, but for the sake of neatness I'd rather access it directly.

Is this possible? ..and if it is, how do I approach it?

Ta

Community · Accepted Answer · 2023-11-17 20:38:18Z

2

Either

fetch as array instead of stdClass or
typecast to (array) or
use a custom class that implements ArrayAccess.

edited Nov 17, 2023 at 20:38

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answered Aug 2, 2010 at 15:46

Gordon

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1 Comment

David Yell Over a year ago

Eish, I'll just assign it to a variable then :) Cheers for the reply

Richard JP Le Guen · Accepted Answer · 2010-08-02 15:52:01Z

0

Assuming that $domains is your stdClass object which you wish was an array, you could try using variable variables:

echo $domains->{$k+1}->alert_type;

The real problem though is that you have a bunch of stdClass objects. Are you storing these in a session and then reading them later, or are you neglecting to include a file or something... ?

answered Aug 2, 2010 at 15:52

Richard JP Le Guen

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1 Comment

David Yell Over a year ago

I don't think it's missing the database class, or my queries wouldn't work. It's just a straight up db -> display page

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