issue with array declaration in bash? [duplicate]

Question

Trying to create a bash script to pick a random radio ip to make mplayer play:

#!/bin/sh
#A simple script to run random radio channels on mplayer

radio = (http://162.253.40.181:8808 http://195.154.69.121:8000 http://108.163.197.114:8103 http://216.245.201.73:9910 http://5.63.145.172:7090)

current = echo $[ 1 + $[ RANDOM % 5 ]]

#echo $current

mplayer $radio{[current]}

I think my array declaration is wrong because the script throws out the following error:

Syntax error: "(" unexpected

Thanks @Cyrus - that helped, but I am not able to work on all the suggestions there but I will figure it out eventually. — Whitewolf
– Whitewolf, Commented Dec 24, 2015 at 21:46

shellter · Accepted Answer · 2015-12-24 21:58:42Z

2

var assignments in shell cannot have space chars on either side of =, hence you need

 radio=(http://162.253.40.181:8808 http://195.154.69.121:8000 http://108.163.197.114:8103 http://216.245.201.73:9910 http://5.63.145.172:7090)

Once you fix that, your line

 current = echo $[ 1 + $[ RANDOM % 5 ]]

has some problems

Try

 current=$(( $RANDOM % 5 ))

or if you really need the 1+, then

 current=$(( 1+ $RANDOM % 5 ))

AND, per your comment/question, you need

mplayer $radio{[$current]}

IHTH

edited Dec 24, 2015 at 21:58

answered Dec 24, 2015 at 21:33

shellter

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2 Comments

Whitewolf Over a year ago

Will radio[current] point to the right element in the array?

shellter Over a year ago

you're correct, that is a problem, see edit at end of my A. Good luck.

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