I have got two arrays in my Jquery
var results = ["1","2","3","4","5","6"];
var chosen = ["1","A","3","B","5","C"];
How can i delete everything from results that exists in chosen?
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3 Answers
for(var i = 0; i < chosen.length; i++){
if(results.indexOf(chosen[i]) > -1){
results.splice(results.indexOf(chosen[i]),1);
}
}
console.log(results);
results = > 2,4,6
Comments
Try,
var results = ["1","2","3","4","5","6"];
var chosen = ["1","A","3","B","5","C"];
var cnt = chosen.length;
while(--cnt, cnt >= 0) {
if(results.indexOf(chosen[cnt]) > -1){
chosen.splice(cnt,1)
}
}
Delete everything from second array that exists in first array Jquery
so console.log(chosen); // "A","B","C" will be the result.
answered Apr 1, 2016 at 13:26
Rajaprabhu Aravindasamy
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1 Comment
Rajaprabhu Aravindasamy
@MuradEmi Glad to help! :) Try to press tick mark present inside anyone of the answers here, that helped you solving your issue. But this is not a compulsion. :)
do a foreach on results and check if the value is contained into the chosen array, if it is, remove the value
2 Comments
Murad Emi
Actually i did it like this $.each( results, function( key, value ) { if(jQuery.inArray(value, chosen) !== -1){ jQuery.grep(results, function(values) { return value !=values ; }); } });
Astaroth
Why would you use functions for a thing that you can do with a for? And of top of that, they're not even native javascript functions. I think both answers are better than using jquery each and grep, and faster.