JQuery .find() function for multiple array

Question

Here is my code snippet

for (var k = 0; k < link_list.length; k++) {
    var service_list = document.getElementsByName("service_info");
    service_list = $(service_list).children("div[name=service_info_element]");
    for (var i = 0; i < service_list.length; i++){
        var service_info = {};
        service_info["service_name"] = $(service_list[i]).find("select[name=service_name]").val();
        service_info["service_type"] = $(service_list[i]).find("input[name=service_type]").val();

    }

How can I get $(service_list[i]).find("select[name=service_name]").val() and $(service_list[i]).find("input[name=service_type]").val(); for each link_list[k] inside the second loop. I mean I need something like link_list[k].service_list[i].find("select[name=service_name]").val()

I faced some problems with .each() to get my desired result. Anyway I have solved it using the following line: var service_list = $(link_list[k]).find("div[name=service_info_element]"); thanks for your suggestions :) — Rajshakhar Paul Rajesh
– Rajshakhar Paul Rajesh, Commented Apr 28, 2016 at 14:21

Tousif Ahmad · Accepted Answer · 2016-04-28 09:36:51Z

1

You can try this it'll work $('service_list[i]').find('select[name=service_name]').filter([0,3,4]).anything();

answered Apr 28, 2016 at 9:36

Tousif Ahmad

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progrAmmar · Accepted Answer · 2016-04-28 07:56:16Z

0

Try the following:

link_list[k].service_list[i].find("select[name=service_name]").each(function(i, element){
    var val = $(this).val(); // or element.val()
});

answered Apr 28, 2016 at 7:56

progrAmmar

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