Write a loop using python

Question

I need to print value with some size using condition.

size, url
1 https://api-glb-ams.smoot.apple.com/user_guid?
3257 https://init.itunes.apple.com/WebObjects/MZInit.woa/wa/signSapSetupCert
0 http://engine.rbc.medialand.ru/code?
35 http://www.google-analytics.com/collect?
0 http://engine.rbc.medialand.ru/test?
0 http://engine.rbc.medialand.ru/code?

I get it in loop and I try to get all url, where size more than 43.

if not size:
    continue
elif size[0] < 43:
    continue
else:
    print size[0], url

If condition works, but elif doesn't. It print all size and url

Are you reading this from a file? If then the issue can be with the string type — nu11p01n73R
– nu11p01n73R, Commented May 16, 2016 at 8:45

TigerhawkT3 · Accepted Answer · 2016-05-16 08:46:01Z

2

In Python 2, which you are using, strings can be compared to integers. Strings always compare as being larger than integers.

>>> '35' < 43
False

To solve this, wrap the string in an int() call:

>>> int('35') < 43
True

For your program:

elif int(size[0]) < 43:

answered May 16, 2016 at 8:46

TigerhawkT3

49.5k6 gold badges65 silver badges101 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Write a loop using python

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related