Executing Perl Scripts Within Variables in Bash

Question

Following my professors exact instructions, I am trying to create a variable named EGG that contains 100 'A's by running this command from my Kali VM:

root@kali:~# EGG='perl -e "print 'A'x100"'

This is my result when attempting to echo the variable:

root@kali:~# echo $EGG
perl -e "print Ax100"

In my professor's demonstration, his variable contained 100 'A's as is expected. Any suggestions on how to fix this?

you can also show your professor this: mywiki.wooledge.org/BashFAQ/082 on why $() is preferred over `` — Sundeep
– Sundeep, Commented Sep 16, 2016 at 3:53

ysth · Accepted Answer · 2016-09-16 03:38:21Z

7

You need to use back ticks in the shell to capture a command's output.

# EGG=`perl -e "print 'A'x100"`

answered Sep 16, 2016 at 3:38

ysth

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2 Comments

Lance_P Over a year ago

Oh, thank you so much. I was mistaking them for apostrophes on the replay of my professor's lecture.

Gordon Davisson Over a year ago

This is one of the reasons that $( ) (e.g. EGG=$(perl -e "print 'A'x100")) is preferred over backquotes -- it's much harder to misread.

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