String.format in javascript query

Question

I'm trying to write a java code into javascript.

public static String generateTimeRange( start,  end) {
    return String.format("%02d:%02d-%02d:%02d", start / 60, start % 60, end / 60, end % 60);
}

Basically this will return a time 00:10 - 00:20 (if 10 and 20 are arguments)

I want to write the same function in javascript but having a hard time. Can someone help?

function generateTimeRange( start,  end) {
    return String.format("{0}:{1}-{2}:{3}", start / 60, start % 60, end / 60, end % 60);
}

Since javascript does not have String.format, I've used the following code:

if (!String.format) {
  String.format = function(format) {
    var args = Array.prototype.slice.call(arguments, 1);
    return format.replace(/{(\d+)}/g, function(match, number) { 
      return typeof args[number] != 'undefined'
        ? args[number] 
        : match
      ;
    });
  };
}

But it kinda prints the following

generateTimeRange(10,20);
"0.16666666666666666:10-0.3333333333333333:20"

Looks like I'm not doing the %02d. How do i do it in javascript?

Thanks

github.com/alexei/sprintf.js

zerkms
– zerkms

2016-11-02 04:19:01 +00:00
Commented Nov 2, 2016 at 4:19 — zerkms
– zerkms, Commented Nov 2, 2016 at 4:19

Sreekanth · Accepted Answer · 2016-11-02 04:28:02Z

1

You could just return a concatenate string or you could do it with Template literals

function generateTimeRange(start, end) {
  return Math.floor(start / 60) + ":" + Math.floor(start % 60) + "-" + Math.floor(end / 60) + ":" + Math.floor(end % 60);
}

function generateTimeRangeInterpolation(start, end) {
  var sPrefix = Math.floor(start / 60),
    start = Math.floor(start % 60),
    ePrefix = Math.floor(end / 60),
    end = Math.floor(end % 60);

  return `${sPrefix}:${start}-${ePrefix}:${end}`
}

console.log(generateTimeRange(10, 20));
console.log(generateTimeRangeInterpolation(10, 20));

answered Nov 2, 2016 at 4:28

Sreekanth

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1 Comment

TechnoCorner Over a year ago

Thank you for your response.

Alongkorn · Accepted Answer · 2016-11-02 04:24:26Z

1

javascript es6 introduces string template that can solve your problem.

function _pad(_n, width) {
  const z = '0';
  const n = _n + '';
  return n.length >= width ? n : new Array(width - n.length + 1).join(z) + n
}

function formatTime(start, end) {
  const minStart = _pad(parseInt(start / 60), 2)
  const secStart = _pad(start % 60, 2)
  const minEnd = _pad(parseInt(end / 60), 2)
  const secEnd = _pad(end % 60, 2)
  
  return `${minStart}:${secStart}-${minEnd}:${secEnd}`
}

console.log(formatTime(100, 120)) // 01:40-02:00
console.log(formatTime(60, 61)) // 01:00-01:01

answered Nov 2, 2016 at 4:24

Alongkorn

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Comments

Community · Accepted Answer · 2020-06-20 09:12:55Z

1

Padded zeros, correct? I use this one from this post

SNIPPET

String.prototype.zer0Pad = function(pad, siz) {
  var str = this;
  var len = parseInt(siz, 10);
  while (str.length < len) {
    str = pad + str;
  }
  return str;
}

var number = '7';
var digits = '2';
var padding = '0';

var result1 = number.zer0Pad(padding, digits);

var string = '42';

var result2 = string.zer0Pad(0, 4);

console.log('result1: ' + result1 + '\nresult2: ' + result2);

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Nov 2, 2016 at 4:42

zer00ne

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Comments

scai · Accepted Answer · 2016-11-02 04:25:46Z

0

i guess the quesions changes to how to make a fixed length num. you can use substr like :

function(num) { ( "00" + parseInt(num)).substr(-2); }

answered Nov 2, 2016 at 4:25

scai

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