Converting my php array to equivalent jQuery Array

Question

I have an array in PHP and want to use that data inside my Jquery, I have converted that to json and here is my full code.

$mine = array(
'new' => 'new',
'old' => 'old'
);

and I have converted it like this

$result = json_encode(array_values($cat));

and now I got my results like show below:

[{"new":"new","old":"old"}]

this is wrong one, because I want it to be like this way.

[
{"new":"new"},
{"old":"old"}
]

I don't know where am I doing any thing wrong but I am unable to get this simple thing done ... any one to help me out of this simple question please ... I really have been through many earlier questions like json_encode sparse PHP array as JSON array, not JSON object

But still unable to get this work for me, any one there to help me out pelase ???

Try to use $result=json_encode($mine) in php and $.parseJSON(json) in jQuery. — Miron
– Miron, Commented Dec 13, 2016 at 13:47
In the comments to an answer you showed your "actual code". Please put it in the question too, since it seems to be pretty different. — Aioros
– Aioros, Commented Dec 13, 2016 at 15:42

Iarwa1n · Accepted Answer · 2016-12-13 13:52:41Z

1

Your array has to look like this in PHP:

$mine = array(
array('new' => 'new'),
array('old' => 'old')
);

json_encode transforms a php array to a json object ( {} )if it is a dictionary (Associative) and transforms it to a json array ( [] ) if it is a list without keys.

answered Dec 13, 2016 at 13:52

Iarwa1n

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3 Comments

laraib Over a year ago

here is my actual code $cat = array(); $categories = $categories = get_categories(array('hide_empty' => true)); //print_r($categories); foreach($categories as $category){ $cat['name'][$category->name] = $category->slug; }

laraib Over a year ago

Array ( [0] => Array ( [another] => another ) [1] => Array ( [Uncategorized] => uncategorized ) ) now this is my array in php ... how can i make it like I already shown structure in jquery ?

Iarwa1n Over a year ago

This looks already right as your key/value pairs are inside extra array. Does json_encode not work correclty with this?

teo van kot · Accepted Answer · 2016-12-13 13:50:26Z

0

You got a bit wrong structure of your php object it should be:

$mine = array(
   array('new' => 'new'),
   array('old' => 'old')
);

Check example.

answered Dec 13, 2016 at 13:50

teo van kot

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2 Comments

laraib Over a year ago

Array ( [0] => Array ( [another] => another ) [1] => Array ( [Uncategorized] => uncategorized ) ) now this is my array in php ... how can i make it like I already shown structure in jquery ?

laraib Over a year ago

the problem is that I am getting that data from ajax success method and then pushing that respone json to my jquery array ... then I want to use that array ... any one who can guide me properly plz ?

GhanuBha · Accepted Answer · 2016-12-13 15:13:16Z

0

You can also do like this:

var encodedVar=json_encode($array_nm);
var js_array=$.paseJSON(encodedvar);
for(var i=0;i<js_array.length;i++){
    console.log(js_array[i]);//it will display value by index just like php array....
}

answered Dec 13, 2016 at 15:13

GhanuBha

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