Extract chars from one string using regex python

Question

How do I extract a certain word after a certain character in regex python?

For example: given = 'abcdefghijkl"mnop:"qfdf"gg"'

I want to get qfdf which is afer "mnop:" and before "gg". The given string is one string, no whitespace.

So far I can do \w+"mnop:" to get to qfdf"gg", but I don't know any \K function in python regex. I am also aware of using (?<=...), but this only takes a fixed width of characters.

Thanks!

@codeforester is regexr.com for python? I thought this was for js.. — John Avant
– John Avant, Commented Feb 9, 2017 at 4:56

heemayl · Accepted Answer · 2017-02-09 04:56:07Z

1

Leverage lookarounds:

(?<="mnop:")[^"]+(?="gg")

The zero width positive lookbehind, (?<="mnop:"), makes sure the desired portion is preceded by "mnop"
[^"]+ matches one or more characters that are not "
The zero width positive lookahead, (?="gg"), makes sure the desired match is followed by "gg"

Example:

In [6]: given = 'abcdefghijkl"mnop:"qfdf"gg"'

In [7]: re.search(r'(?<="mnop:")[^"]+(?="gg")', given).group()
Out[7]: 'qfdf'

answered Feb 9, 2017 at 4:56

heemayl

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