Bash - iterate multiple variable with for loop index

Question

How to use for (( )) loop with index variable for this script? I can't find any examples to do that..

code:

var1=$1
url="http://www.google.com/"

# maybe use a for loop here??

# Okay now if I use getopts - @Hannu

while getopts ":p:e:" o; do
case "${o}" in
        p)
        page+=("$OPTARG")
        ;;
        e)
        extension+=("$OPTARG")
        ;;
esac
done
shift $((OPTIND -1))

#I need a better for loop here - which can expand both variables

for val in "${extension[@]}"; # how to use for (( )) here?
do

# FAIL - pass first switch arguments -p and -e to for loop

echo "URL is http://www.google.com/$page.$val
done

OUTPUT: # closest I can get to.. first -p argument

./test.sh -p help -p contact -e html -e php

URL is http://www.google.com/help.html

URL is http://www.google.com/help.php

I want the output to be like..

URL is http://www.google.com/help.html

URL is http://www.google.com/contact.php

tso · Accepted Answer · 2017-05-19 10:44:49Z

1

voila:

#!/bin/bash
var1=$1
url="http://www.google.com/"

# maybe use a for loop here??

# Okay now if I use getopts - @Hannu

while getopts ":p:e:" o; do
case "${o}" in
        p)
        page+=("$OPTARG")
        ;;
        e)
        extension+=("$OPTARG")
        ;;
esac
done
shift $((OPTIND -1))


for ((i=0;i<${#extension[@]};++i));
do
echo "URL is www.google.com/${page[i]}.${extension[i]}"
done

answered May 19, 2017 at 10:44

tso

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3 Comments

user630702 Over a year ago

awesome! Thank you

user630702 Over a year ago

Can you explain that line? " i<${#extension[@]} ".How did it work.. i=0; and then i is less than #value? What is it called? So I can search myself :)

tso Over a year ago

${#arrayname[@]} gives you the length of the array. :))

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