Suppose I have an array:
["Team A, 6, 2, 12","Team B, 7, 1, 14","Team C, 4, 4, 8"]
How could I sort the array such that the last numbers in each array element are in descending order? That is:
["Team B, 7, 1, 14","Team A, 6, 2, 12","Team C, 4, 4, 8"]
I have checked out various compare functions, but I cannot figure out how to tailor them to this specific situation.
Use a regex to get last digits in each string in Array#sort()
let reg = /\d+$/;
let arr = ["Team A, 6, 2, 12","Team B, 7, 1, 14","Team C, 4, 4, 8"];
arr.sort((a, b) => reg.exec(b) - reg.exec(a));
console.log(arr)You have to define your own compare function
var arr = ["Team A, 6, 2, 12","Team B, 7, 1, 14","Team C, 4, 4, 8"];
function compare(a,b){
var vala = a.split(',').pop();
var valb = b.split(',').pop();
return valb-vala;
}
arr.sort(compare);
console.log(arr);
- on 2 numeric strings casts each to number automatically
return b.split(',').pop() - a.split(',').pop() if you wanted a one-liner.Basically, all you need to do is extract that last number, then use it in your comparason:
var myArray = ["Team A, 6, 2, 12","Team B, 7, 1, 14","Team C, 4, 4, 8"];
function sorter(item1, item2) {
const split1 = item1.split(",");
const split2 = item2.split(",");
const num1 = split1[split1.length - 1] || 0;
const num2 = split2[split2.length - 1] || 0;
return num2 - num1;
}
myArray.sort(sorter)
console.log(myArray)
myArray.sort((item1, item2) => Number(item2.split(",").pop()) - Number(item1.split(",").pop()));Number() calls, because the - operator coerces both operands to numbers automatically.