How to get different values from 2 object arrays using underscore js

Question

How to get different values from 2 object arrays using underscore js. I have 2 object arrays like this

var a = [{
    "asset_id": 1,
    "asset_type": 2
}, {
    "asset_id": 1,
    "asset_type": 3
}, {
    "asset_id": 3,
    "asset_type": 3
}, {
    "asset_id": 5,
    "asset_type": 2
}, {
    "asset_id": 9,
    "asset_type": 3
}, {
    "asset_id": 10,
    "asset_type": 3
}];

var b = [{
    "asset_id": 1,
    "asset_type": 2
}, {
    "asset_id": 1,
    "asset_type": 3
}, {
    "asset_id": 3,
    "asset_type": 3
}];

My result should be like this

[{
    "asset_id": 5,
    "asset_type": 2
}, {
    "asset_id": 9,
    "asset_type": 3
}, {
    "asset_id": 10,
    "asset_type": 3
}]

Is there any inbuilt functions to this in underscorejs

What are you filtering from your array of as and bs to be within your result? Your result looks like it's just picking the last 3 items form array a. — Kristian Roebuck
– Kristian Roebuck, Commented Dec 5, 2017 at 13:46
@KristianRoebuck the result is non-common items from 2 object array — byteC0de
– byteC0de, Commented Dec 5, 2017 at 13:47
Please provide a proper explanation of the criteria for all to read. People shouldn't have to be diff tools to understand. Also show what you have tried that isn't working — charlietfl
– charlietfl, Commented Dec 5, 2017 at 13:48
In your example you have some objects in your results are exist within a and b. It's probably worth correcting that. — Kristian Roebuck
– Kristian Roebuck, Commented Dec 5, 2017 at 13:49

Mikhail Katrin · Accepted Answer · 2017-12-05 13:53:40Z

1

You could achieve it using _.reject and _.findWhere.

var a = [{
    "asset_id": 1,
    "asset_type": 2
}, {
    "asset_id": 1,
    "asset_type": 3
}, {
    "asset_id": 3,
    "asset_type": 3
}, {
    "asset_id": 5,
    "asset_type": 2
}, {
    "asset_id": 9,
    "asset_type": 3
}, {
    "asset_id": 10,
    "asset_type": 3
}];

var b = [{
    "asset_id": 1,
    "asset_type": 2
}, {
    "asset_id": 1,
    "asset_type": 3
}, {
    "asset_id": 3,
    "asset_type": 3
}];

var newArr = _.reject(a, function(obj) {
  return _.findWhere(b, obj)
})

console.log(newArr)

<script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore-min.js"></script>

answered Dec 5, 2017 at 13:53

Mikhail Katrin

2,4041 gold badge12 silver badges17 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

How to get different values from 2 object arrays using underscore js

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related