Insert to list with variable names in python

Question

I have three lists, named list0, list1 and list2.
Here is what i want to do

for n in range(10):
    x = n%3
    listx.append(n)

where x can be 0, 1 or 2. How can I do this? Basically, I don't want to create 3 if/elif cases but just change the third line in above program

PS - I know this not the best method for this problem but my project is quite different from this

Why don't you make it a list of lists or a dictionary of lists? Then you can do list[x].append(n). — L3viathan
– L3viathan, Commented Dec 6, 2017 at 7:55

kabanus · Accepted Answer · 2017-12-06 07:57:45Z

1

Why not a list of lists?

lists = [[],[],[]]
for n in range(10):
    list[n%3].append(n)

list1,list2,list3 = lists

or just use lists[i], which would scale better to bigger primes.

answered Dec 6, 2017 at 7:57

kabanus

26.3k7 gold badges48 silver badges79 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

zwer · Accepted Answer · 2017-12-06 08:02:39Z

0

If you insist, you can use locals() (or globals() to get your lists from the outer scope) to get your lists by name:

list0, list1, list2 = [], [], []

for n in range(10):
    x = n % 3
    locals()["list" + str(x)].append(n)

print(list0, list1, list2)  # [0, 3, 6, 9] [1, 4, 7] [2, 5, 8]

But that's really a bad practice.

answered Dec 6, 2017 at 8:02

zwer

25.9k3 gold badges53 silver badges70 bronze badges

1 Comment

kabanus Over a year ago

Even worse practice if we're going there: eval("list"+str(x)+".append("+str(n)+")")

Collectives™ on Stack Overflow

Insert to list with variable names in python

2 Answers 2

Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related