How to dynamically push an array using spread operator Javascript

Question

[
  {
    "details": {
      "name": "john",
      "point": "20"
    },

    "list": {
      "number": "30",

    }
  },
  {
    "details": {
      "name": "doe",
      "point": "25"
    },
    "list": {
      "number": "30",

    }
  }
]

This is what i am trying to do, i am getting the data from the store and if the response is only one i use data = getData[0].details and if the response is more than one then i push the data using [...data, ...getData[1].details] if there are more than one data how can i achieve. thanks in advance

 let data:any = [];
     this.store
              .pipe(
                select(getData),
                map((getData,i) => {
                  if (getData) {
                      data = [...data, ...getData[i].details]
                  }
             return data;
                })
             )

I'm very confused what are trying to do here, can you elaborate a bit more in your question? Please include an example of what the desired output would be. Also, I don't understand how select(getData) can work, isn't getData defined only inside map's callback? — CherryDT
– CherryDT, Commented Mar 8, 2020 at 23:35

Mohammed Samir · Accepted Answer · 2020-03-08 23:51:39Z

1

I think you want to get an array of the details. In this case you can say.

let data = [
  {
    "details": {
      "name": "john",
      "point": "20"
    },

    "list": {
      "number": "30",

    }
  },
  {
    "details": {
      "name": "doe",
      "point": "25"
    },
    "list": {
      "number": "30",

    }
  }
];

let details = data.map(a => a.details);

console.log(details);

answered Mar 8, 2020 at 23:51

Mohammed Samir

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Comments

Sweet Chilly Philly · Accepted Answer · 2020-03-09 00:09:22Z

1

I think i understand what you mean:

What I would do is map over your getData response and add to the original array on each iteration. It wont matter if there is 1 or many in the getData array:

getData.map(x => $data.push(x.details));

answered Mar 9, 2020 at 0:09

Sweet Chilly Philly

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