Returning a variable name from an array in shell script

Question

I want to append the value as $EC5 in my newlist in shell script. However, it is currently storing value as 11 in newlist array.

EC2=0
EC3=0
EC4=0
EC5=11
return_codes=( $EC2 $EC3 $EC4 $EC5)
newlist=()

for i in "${return_codes[@]}";
do
    if [[ $i -ne 0 ]]
        then
            newlist+=($i)
    fi
done

Kindly Help.

$EC5 is 11. Or do you mean you want to store the string EC5 itself? Leave out the $ then. When you run return_codes=( $EC2 $EC3 $EC4 $EC5 ), that does return_codes=( 0 0 0 11 ); the place where each of those numbers originally came from is lost. — Charles Duffy
– Charles Duffy, Commented Mar 18, 2020 at 21:45
There are no arrays in POSIX [shell] so you should add the proper tag for the shell you are using. [bash]? — David C. Rankin
– David C. Rankin, Commented Mar 18, 2020 at 22:26

that other guy · Accepted Answer · 2020-03-18 21:14:59Z

2

Instead of storing the variable's value, you can store its name and look that up:

EC2=0
EC3=0
EC4=0
EC5=11
return_codes=( EC2 EC3 EC4 EC5)
newlist=()

for i in "${return_codes[@]}";
do
    if [[ ${!i} -ne 0 ]]
        then
            newlist+=($i)
    fi
done

answered Mar 18, 2020 at 21:14

that other guy

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